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yawa3891 [41]
3 years ago
5

The display provided from technology available below results from using data for a smartphone​ carrier's data speeds at airports

to test the claim that they are from a population having a mean less than 4.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative​ hypotheses, test​ statistic, P-value, and state the final conclusion that addresses the original claim.

Mathematics
1 answer:
Flauer [41]3 years ago
7 0

Answer:

The null hypothesis was failed to be rejected.

Step-by-step explanation:

The complete question is:

The display provided from technology available below results from using data for a smartphone​ carrier's data speeds at airports to test the claim that they are from a population having a mean less than 4.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative​ hypotheses, test​ statistic, P-value, and state the final conclusion that addresses the original claim. The summary statistics are n=93​, x overbar=3.92​, s=0.51.

Solution:

The hypothesis is:

<em>H</em>₀<em>:</em><em> </em>The smartphone​ carrier's mean data speed at airports is not less than 4.00 Mbps, i.e. <em>μ</em> ≥ 4.00.

<em>H</em>ₐ<em>:</em><em> </em>The smartphone​ carrier's mean data speed at airports is less than 4.00 Mbps, i.e. <em>μ</em> < 4.00.

Compute the test statistic as follows:

t=\frac{\bar x-\mu}{s/\sqrt{n}}\\\\=\frac{3.92-4.00}{0.51/\sqrt{93}}\\\\=-1.51

Compute the <em>p</em>-value as follows:

p-value=P(t_{n-1}

*Use a <em>t</em>-table.

*If the desired degrees of freedom is not provided use the next higher value.

The <em>p</em>-value = 0.066 > <em>α</em> = 0.05

The null hypothesis was failed to be rejected.

Thus, it can be concluded that the smartphone​ carrier's mean data speed at airports is not less than 4.00 Mbps.

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