Do you guys now the answer I need it ASAP please
2 answers:
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Since we have a rectangle triangle, then we can find the other side of the triangle using the Pythagorean theorem.
We have then:
Then the surface area is given by the sum of the areas.
Triangle of the base and the top:
Rectangle 1:
Rectangle 2:
Rectangle 3:
Finally, the surface area is:
Substituting values:
Answer:
The surface area of a right triangle prism is:
B. 132
We have then:
Then the surface area is given by the sum of the areas.
Triangle of the base and the top:
Rectangle 1:
Rectangle 2:
Rectangle 3:
Finally, the surface area is:
Substituting values:
Answer:
The surface area of a right triangle prism is:
B. 132
Answer:
Therefore, the two options for triangles to be congruent using AAS are
1. BC ≅ MQ (Additional information)
2. AC ≅ RQ (Additional information)
Step-by-step explanation:
Given:
∠CAB =∠MRQ = 29°
∠ABC = ∠RMQ = 116°
To Prove:
Δ ABC ≅ ΔRMQ by AAS congruence test which additional information is required
Proof:
<u>Case 1.</u>
In Δ ABC and Δ RMQ
∠CAB =∠MRQ = 29° ……….{Given}
∠ABC = ∠RMQ = 116° ..……..{Given}
BC ≅ MQ ……….{Additional information required}
Δ ABC ≅ Δ RMQ ….{By Angle-Angle-Side congruence test}
<u>Case 2.</u>
In Δ ABC and Δ RMQ
∠CAB =∠MRQ = 29° ……….{Given}
∠ABC = ∠RMQ = 116° ..……..{Given}
AC ≅ RQ ……….{Additional information required}
Δ ABC ≅ Δ RMQ ….{By Angle-Angle-Side congruence test}
Therefore, the two options for triangles to be congruent using AAS are
1. BC ≅ MQ (Additional information)
2. AC ≅ RQ (Additional information)
