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siniylev [52]
3 years ago
10

HELP!!!!!!!!! ASP

Mathematics
2 answers:
Pavel [41]3 years ago
8 0

Answer:

D. (2,15) and (4,25)

Step-by-step explanation:

The slope of the line that passes through (-9,4) and (1,2) is -1/5 so in order to find the slope that is perpendicular to it, you need to find out with of these pairs of points has a slope that is the negative reciprocal of -1/5 which is 5. So the only points that have the slope of 5 are (2,15) and (4,25).

~Please mark me as brainliest :)

Anarel [89]3 years ago
3 0

Answer:

D

Step-by-step explanation:

What you need to do is find the slope of both lines. Perpendicular lines are the negative inverse of each other. The slope of the lie between points R and F is  (2-4)/(1+9)=-1/5. Now you need to find the line where the slop is 5. If you look at D, the slope of the line those points lie on is (25-15)/(4-2)=5 which makes D the answer.

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Explicit formulas for arithmetic sequences are derived from terms in arithmetic sequences. It helps to find each term in arithmetic progression easily. The arithmetic progression is a1, a2, a3, ..., an. where the first term is denoted as 'a', we have a = a1, and the tolerance is denoted as 'd'. The tolerance formula is d = a2 - a1 = a3 - a2 = an - an - 1. The nth term of the arithmetic progression represents the explicit formula for the arithmetic progression.

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7 0
1 year ago
Help in math plzzddddddddddddddddd
melomori [17]

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3 0
3 years ago
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4 0
3 years ago
Find the value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2
soldier1979 [14.2K]

The value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2 is -2

<u>Solution:</u>

Given that line is passing through point (-5, 2) and (3, r)

Slope of the line is \frac{-1}{2}

Need to determine value of r.

Slope of a line passing through point \left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right)  is given by following formula:

\text { Slope } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}  --- eqn 1

\text { In our case } x_{1}=-5, y_{1}=2, x_{2}=3, y_{2}=\mathrm{r} \text { and } m=-\frac{1}{2}

On substituting the given value in (1) we get

\begin{array}{l}{-\frac{1}{2}=\frac{r-2}{3-(-5)}} \\\\ {\text { Solving the above expression to get value of } r} \\\\ {=>-\frac{1}{2}=\frac{r-2}{3+5}} \\\\ {=>-8=\frac{r-2}{3+5}} \\\\ {=>-8=2(r-2)} \\\\ {=>-8=2 r-4} \\\\ {=>2 r=-8+4} \\\\ {=>2 r=-4} \\\\ {=>r=\frac{-4}{2}=-2}\end{array}

Hence the value of "r" is -2

8 0
3 years ago
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