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ozzi
2 years ago
7

An algebra 2 question..... about cosine.

Mathematics
1 answer:
zvonat [6]2 years ago
6 0

Answer:d i believe

Step-by-step explanation:

if im wrong i will get hate comments, im already hated by everyone so it dont matter

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Ronald is making hats and scarves for charity. He has enough yarn to make 5 hats and 8 scarves. Takes him 12 hrs to knit a hat,
kari74 [83]

Constraints are simply the subjects of an objective function.

The inequality that represents the constraint is: 12x + 6y \le 20

Represent the number of hats with x, and the number of scarves with y.

From the question, we have:

  • He spends 12 hours to knit a hat
  • He spends 6 hours to knit a scarf

So, the equation of the total time spent is:

Time = 12x + 6y

This time spent is not more than 20 hours.

So, the inequality is

12x + 6y \le 20

Hence, the inequality that represents the constraint is: 12x + 6y \le 20

Read more about constraints at:

brainly.com/question/24574823

3 0
2 years ago
The difference between a number divided by 3 and 4 is 20.
Alexxandr [17]
Let, the number be "a"

Now, according to the question,
\frac{a}{3} - 4=20

\frac{a-12}{3} =20

a-12 =20*3

a-12=60

a = 60 + 12

a = 72


So, the number is 72

7 0
3 years ago
Read 2 more answers
Which is a way to check the answer 120 divided by 4 = 30
Andru [333]
Multiply 4 and 30. If the answer is 120, then you are correct.
5 0
3 years ago
Read 2 more answers
Identify the fractions as proper, improper, or mixed; however, if the fraction is equivalent to one, indicate so. 3 1/8
Tcecarenko [31]

Answer:

Hello!  3 1/8 is a mixed fraction.  

Step-by-step explanation:


8 0
3 years ago
What is the interquartile range for this data?<br><br> 120, 140, 160, 180, 200, 220, 240
Nutka1998 [239]

Step-by-step explanation:

The data is already in ascending order.

The lower half of the data (120, 140, 160)

has the median 140.

180 is the median of the entire data.

The upper half of the data (200, 220, 240)

has the median 220.

Interquartile Range = 220 - 140 = 80.

6 0
3 years ago
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