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ozzi
3 years ago
7

An algebra 2 question..... about cosine.

Mathematics
1 answer:
zvonat [6]3 years ago
6 0

Answer:d i believe

Step-by-step explanation:

if im wrong i will get hate comments, im already hated by everyone so it dont matter

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HELP ME Kiran is using long division to find 623 = 7
Oksana_A [137]

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B

Step-by-step explanation:

because TRUST ME

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3 years ago
Please please help worth lots of points Given ƒ(x) = x - 1, complete Parts A and B. Part A: Using the table provided, create fiv
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What statement is true about the product sqrt of 2 (5+ sqrt 8)
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4 years ago
Find all complex solutions of 7x^2-7x+3=0
Sedaia [141]

Answer:

The complex solutions are

x =  (\frac{7-\sqrt{35}  i }{42} , ) x =  \frac{7 + \sqrt{35} i }{42})

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given equation  7 x² - 7 x +3=0

                     x =  (\frac{-b -\sqrt{b^{2}-4ac } }{2ac} ,  \frac{-b +\sqrt{b^{2}-4ac } }{2ac})

Given standard equation

                         a x² +b x +c =0

 a = 7 , b= -7 and c=3

<u><em>Step(ii):-</em></u>

<u><em></em></u>x =  (\frac{-(-7) -\sqrt{(-7)^{2}-4(7)(3) } }{2(7)(3)} ,  \frac{-(-7) +\sqrt{(-7)^{2}-4(7)(3) } }{2(7)(3)})<u><em></em></u>

<u><em></em></u>x =  (\frac{7-\sqrt{(49-84 } }{42} ,  \frac{7 +\sqrt{(49-84 } }{42})<u><em></em></u>

x =  (\frac{7-\sqrt{35i^{2} }  }{42} ,  \frac{7 + \sqrt{35i^{2} }  }{42})

x =  (\frac{7-\sqrt{35}  i }{42} ,  \frac{7 + \sqrt{35} i }{42})

<u><em></em></u>

8 0
3 years ago
Y=-5(x+3)^2-1 in standard form
Andre45 [30]

Answer:

y=-5x^{2} -30x-46

Step-by-step explanation:

y=-5(x+3)^{2} -1

y=-5((x+3) (x+3))-1

y=-5(x^{2} +6x+9)-1

y=-5x^{2} -30x-45-1

y=-5x^{2} -30x-46

5 0
3 years ago
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