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2 years ago

What would be the answer to this question?

Mathematics

1 answer:

Iteru [2.4K]2 years ago

3 0

The equation has one solution, x = 0
3x = 4x
-3x both sides
0 = 4x - 3x
0 = x

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Choose the graph of the inequality x >2

schepotkina [342]

Step-by-step explanation:B

4 0

3 years ago

Read 2 more answers

3. (03.06)

lisabon 2012 [21]

Answer:

work is shown and pictured

5 0

3 years ago

Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute

valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

= 3 - 1 = 2

d.f.D = N - k

= 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust Jet red Cloudtran

$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

$s_1^2=19.96154$ $s_2^2=14.68681$ $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

$=\frac{51+51+...+49+49}{35}$

= 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

$=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

$=\frac{127.1143}{2}$

= 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

$=\frac{669.8571}{32}$

= 20.93304

The F-test statistics value is :

$F=\frac{s_B^2}{s_W^2}$

$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

3 0

2 years ago

the second term of a geometric sequence is 18 and the fourth term is 8 find the common ratio . And find the sum of the first 6 t

777dan777 [17]

Answer:

ratio: 2/3
sum: 73 8/9

Step-by-step explanation:

The general term of a geometric sequence is ...

an = a1·r^(n-1)

You have the 2nd and 4th terms, so ...

a2 = a1·r^(2-1) = a1·r

a4 = a1·r^(4-1) = a1·r^3

We can find r from the ratio ...

a4/a2 = (a1·r^3)/(a1·r) = r^2 = 8/18 = 4/9

Then r is ...

r = √(4/9) = 2/3 . . . . the common ratio

The first term is ...

a2 = 18 = a1·(2/3)

a1 = (3/2)·18 = 27

The sum of the first 6 terms is ...

Sn = a1·(r^n -1)/(r -1)

S6 = 27·((2/3)^6 -1)/(2/3 -1)

S6 = 27·(64/729-1)/(2/3-1) = (27)(665)/243 = 73 8/9

The sum of the first 6 terms is 73 8/9.

_____

<em>Check on the sum</em>

The first 6 terms are ...

27, 18, 12, 8, 5 1/3, 3 5/9

Their sum is 73 8/9, as above.

8 0

3 years ago

3) WILL MARK BRAINLIEST + 10 POINTS!!!!!! :)

Charra [1.4K]

This is really a long way to go to make something complicated
out of something simple. The last choice does the job.

cos(180) = -1
sin(180) = 0

So 4 [cos(180) + i sin(180) ]

= 4 [ -1 + i (0) ]

= -4 yay!

5 0

3 years ago