To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
Step-by-step explanation:
Since there exists a scalar
λ
λ
(namely
λ=a⋅b
λ=a⋅b
) such that
b=λa
b=λa
, the directions of the two vertices are the same (they are collinear). This implies that
|a⋅b|=|a||b|
|a⋅b|=|a||b|
.
So,
|a|=|(a⋅b)b|=|a||b||b|
|a|=|(a⋅b)b|=|a||b||b|
which implies that
|b|=1
|b|=1
Answer:
E
Step-by-step explanation:
Sjsjdjddjdjdjjddjdjdjdjdjdndnsnsnsbs answer is E
