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4 years ago

If the largest value in a data set is 12 and the range is 3, what is the smallest value in the set?

Mathematics

1 answer:

jeka57 [31]4 years ago

7 0

So the smallest value in the set is 9.

Look at the attached picture

Hope it will help you

Good luck on your assignment

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AB¯ is the diameter of circle T. Point A is located at (-4,2) and point B is located at (2,-8). What are the coordinates of the

postnew [5]

Centre is at the middle or the midpoint of the diameter.

And the formula of midpoint is

$( \frac{x_{1} +x_{2}}{2},\frac{y_{1} +y_{2}}{2})$

For the given question, x1=-4, y1=2, x2=2, y2=-8

So we will get

$( \frac{-4+2}{2}, \frac{2-8}{2} ) = (-1, -3)$

And that's the required centre .

8 0

4 years ago

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5 times 7/8 is greater than, less than or equal to 7/8

Kitty [74]

The answer is greater than.

6 0

4 years ago

Picture attached, please help.

Andrej [43]

Answer:

-1

Step-by-step explanation:

∫x^2 -x +1 dx = x^3/3 -x^2/2 +x evaluated at 1 subtracting the value at 0

1/3 -1/2 +1 - (0/3 -0/2 +0)

5/6

Now lets find

∫x^2 -x +1 dx=x^3/3 -x^2/2 +x evaluated at 2 subtracting the value at 1

2^3/ 3 -2^2/2 +2 - (1/3 -1/2 +1 )

8/3 -2 +2 - (5/6)

8/3 -5/6

11/6

The total is 5/6 - 11/6 = -6/6 or -1

7 0

3 years ago

35 rounded to the nearest hundred

Volgvan

Answer and Explanation: 35 rounded to the nearest 100 is 0. To round to the nearest hundred, you need to first identify the hundreds that are closest to the number you are rounding. For 35, the closest hundred that is lower than 35 is 0, and the closest 100 that is higher than 35 is 100.

7 0

3 years ago

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Using the fractions 2/3 and 3/4 describe how to give two fractions common denominators

Contact [7]

One way is to find the prime factorization for the denominators which are 3 and 4. The prime factorization of 3 would be 1 x 3 and 4 would be 2 x 2. Since we only use prime numbers to find the prime factorization we would have 2 x 2 x 3 = 12 which give us the the least common denominator for 2/3 and 3/4. Final answer is 12.

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3 years ago

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