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AlladinOne [14]
3 years ago
13

AB¯ is the diameter of circle T. Point A is located at (-4,2) and point B is located at (2,-8). What are the coordinates of the

center of this circle?
Mathematics
2 answers:
postnew [5]3 years ago
8 0

Centre is at the middle or the midpoint of the diameter.

And the formula of midpoint is

( \frac{x_{1} +x_{2}}{2},\frac{y_{1} +y_{2}}{2})

For the given question, x1=-4, y1=2, x2=2, y2=-8

So we will get

( \frac{-4+2}{2}, \frac{2-8}{2} ) = (-1, -3)

And that's the required centre .

Rus_ich [418]3 years ago
3 0

Answer:  The required co-ordinates of the center of the circle are (-1, -3).

Step-by-step explanation:  Given that AB is the diameter of circle T. The co-ordinates of point A are (-4, 2) and the co-ordinates of point B are (2, -8).

We are to find the co-ordinates of the center of this circle.

We know that

the center of a circle is the mid-point of any of its diameter.

The co-ordinates of the midpoint of a line segment with endpoints (a, b) and (c, d) are given by

\left(\dfrac{a+c}{2},\dfrac{b+d}{2}\right).

Therefore, the co-ordinates of the midpoint of diameter AB are

\left(\dfrac{-4+2}{2},\dfrac{2-8}{2}\right)\\\\\\=\left(\dfrac{-2}{2},\dfrac{-6}{2}\right)\\\\=(-1,-3).

Thus, the required co-ordinates of the center of the circle are (-1, -3).

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3 years ago
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sergiy2304 [10]

Hello!!

here's ur answer...

given that the volume of cube=343cm³

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