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3 years ago

the equation of a line is y=-1/2x+6. Write an equation in point-slope form for the same line. Explain the steps that you used.

1 answer:

Citrus2011 [14]3 years ago

4 0

Y = -1/2x + 6.....the slope is -1/2 and the y int = 6 or (0,6)

y - y1 = m(x - x1)
slope(m) = -1/2
(0,6)....x1 = 0 and y1 = 6
now we sub
y - 6 = -1/2(x - 0) <==

** You basically just label ur variables and sub them into the point slope form

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Answer:

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Step-by-step explanation:

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3 years ago

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Shtirlitz [24]

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3 years ago

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Step-by-step explanation:

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3 years ago

write a polynomial function of least degree with integral coefficients that has the given zeros. -(1/3), -i

inessss [21]

Answer:

$f(x)=3x^3+x^2+3x+1$

Step-by-step explanation:

If a real number $-\frac{1}{3}$ is a zero of polynomial function, then

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is the factor of this function.

If a complex number $-i$ is a xero of the polynomial function, then the complex number $i$ is also a zero of this function and

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are two factors of this function.

So, the function of least degree is

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If the polynomial function must be with integer coefficients, then it has a form

$f(x)=3x^3+x^2+3x+1$

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3 years ago

Three times two less than a number is greater than or equal to five times the number. Find all of the numbers that satisfy the g

Sholpan [36]

It would be 3(n-2) is greater than or equal to 5n.

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3 years ago

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