The value of the population of the growth of an endangered birth after 5 years is 1975
<h3>How to determine the population after 5 years?</h3>
The population function is given as:
B(t) = 100 + 3/5t^5
At 5 years, the value of t is 5
So, we have
t = 5
Next, we substitute 5 for t in the equation B(t) = 100 + 3/5t^5
This gives
B(5) = 100 + 3/5 * 5^5
Evaluate the exponent
B(5) = 100 + 3/5 * 3125
Evaluate the product
B(5) = 100 + 1875
Evaluate the sum
B(5) = 1975
Hence, the value of the population of the growth of an endangered birth after 5 years is 1975
Read more about exponential functions at:
brainly.com/question/2456547
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Answer:
-57
Step-by-step explanation:
<h2><u>Use BOMAS</u></h2>
B- brackets
O- of
M- multiplication
A- addition
S - subtraction
-3[1+2(4+5)]
first solve what is in the brackets
(4+5) = 9
place 9 in the brackets
-3[1+2(9)]
now multiply the 2 and 9
2*9 = 18
-3[1+18)]
1+ 18 = 19
now multiply the (-3) with 19
= <u>-57</u>
Answer:
Each of them spent $9.35 on meal.
Step-by-step explanation:
Jacob and his three friends ordered an individual pizza and a drink for $6.19.
Total cost of pizza and drink = 6.19 × 4
= $24.76
They also ordered bread sticks for $4.25
Tax on the bill was = $2.39
Tip amount was = $1.50×4 = $6.0
So the total billed amount will be = 24.76 + 4.25 + 2.39 + 6
= $37.4
Since there were four persons including Jacob.
Therefore, each person spend on meal = 
= $9.35
Answer:
The first loan covers 80 percent of the home’s price, while the second covers the remaining 20 percent.
Step-by-step explanation:
they are still a home price percentage
Answer:
The given line segment has a midpoint at (−1, −2).
On a coordinate plane, a line goes through (negative 5, negative 3), (negative 1, negative 2), and (3, negative 1).
What is the equation, in slope-intercept form, of the perpendicular bisector of the given line segment?
y = −4x − 4
y = −4x − 6
y = One-fourthx – 4
y = One-fourthx – 6
y = Three-halvesx + 1
