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lana [24]
3 years ago
6

The area of a lawn is 500 square feet the length is 5 feet longer then the width what are the length and width of the lawn

Mathematics
2 answers:
Oliga [24]3 years ago
6 0

Answer:

width: 20, length: 25

Step-by-step explanation:

area = length x width

since length is 5 feet longer than the width, length = width + 5

so we can replace length with width + 5

500 = (width + 5) x width

500 = w^2 + 5w

0 = w^2 + 5w - 500

w = 20, w = -25

width cannot bc -25 since you cannot have negative width

since width is 20, length is 25 since length = width + 5

width = 20, length = 25

Alona [7]3 years ago
5 0

Step-by-step explanation:

area is base x height so 5 x 100 because as I said area is base x height.

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If u = 2i - j; v= -5i + 4j and w = j find 4u (v -w).
Sedaia [141]

Answer:

-40

Explanation:

Given

u = 2i - j; v= -5i + 4j and w = j

Required

4u(v-w)

4u = 4(2i) = 8i

v - w = -5i + 4j - j

v - w = -5i + 3j

Substitute

4u(v-w)

= 8i(-5i+3j)

= -40(i*i) [since i*i = 1]

= -40

Hence the required solution is -40

5 0
1 year ago
PLEASE HELP
Studentka2010 [4]
<span>The side length for a cube 
with volume 8000cm3 = 8000^(1/3)= 20 m
Cheers,
Stan H.</span>8000=S^3<span>8000=20^3
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3 0
3 years ago
(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti
Rashid [163]

Answer:

The solution

Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

<em>Step(i)</em>:-

Given differential problem

                           y′+3 y=9 t

<em>Take the Laplace transform of both sides of the differential equation</em>

                L( y′+3 y) = L(9 t)

 <em>Using Formula Transform of derivatives</em>

<em>                 L(y¹(t)) = s y⁻(s)-y(0)</em>

  <em>  By using Laplace transform formula</em>

<em>               </em>L(t) = \frac{1}{S^{2} }<em> </em>

<em>Step(ii):-</em>

Given

             L( y′(t)) + 3 L (y(t)) = 9 L( t)

            s y^{-} (s) - y(0) +  3y^{-}(s) = \frac{9}{s^{2} }

            s y^{-} (s) - 7 +  3y^{-}(s) = \frac{9}{s^{2} }

Taking common y⁻(s) and simplification, we get

             ( s +  3)y^{-}(s) = \frac{9}{s^{2} }+7

             y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}

<em>Step(iii</em>):-

<em>By using partial fractions , we get</em>

\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}

  \frac{9}{s^{2} (s+3} =  \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}

 On simplification we get

  9 = A s(s+3) +B(s+3) +C(s²) ...(i)

 Put s =0 in equation(i)

   9 = B(0+3)

 <em>  B = 9/3 = 3</em>

  Put s = -3 in equation(i)

  9 = C(-3)²

  <em>C = 1</em>

 Given Equation  9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

  9 = A s²+3 A s +B(s)+3 B +C(s²)

 <em> 0 = A + C</em>

<em>put C=1 , becomes A = -1</em>

\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}

<u><em>Step(iv):-</em></u>

y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}

y^{-}(s)  =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}

Applying inverse Laplace transform on both sides

L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})

<em>By using inverse Laplace transform</em>

<em></em>L^{-1} (\frac{1}{s} ) =1<em></em>

L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}

L^{-1} (\frac{1}{s+a} ) =e^{-at}

<u><em>Final answer</em></u>:-

<em>Now the solution , we get</em>

Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}

           

           

5 0
3 years ago
________________________
xenn [34]

✩ Answer:

 ✧・゚: *✧・゚:*✧・゚: *✧・゚:*✧・゚: *✧・゚:*  

 \bold{Hello!}\\\bold{Your~answer~is~below!}  

✩ Step-by-step explanation:

 ✧・゚: *✧・゚:*✧・゚: *✧・゚:*✧・゚: *✧・゚:*

✺ Divide both sides by −3. Since −3 is negative, the inequality direction is changed:

  • -3 ÷ -3 = Cancels Out
  • Turns into: \frac{-9}{-3} >5x-2

✺ Divide −9 by −3 to get 3. Since they are both negatives it turns into a positive:

  • -9 ÷ -3 = 3
  • Turns into: 3 > 5x - 2

✺ Swap sides so that all variable terms are on the left hand side. This changes the sign direction once more:

  • Turns into: 5x-2

✺ Add 2 to both sides:

  • Turns into: 5x

✺ Add 3 and 2 to get 5:

  • 3 + 2 = 5
  • Turns into: 5x

✺ Divide both sides by 5. Since 5 is positive, the inequality direction remains the same:

  • 5 ÷ 5 = Cancels Out
  • Turns into: x

✺ Divide 5 by 5 to get 1:

  • 5 ÷ 5 = 1

✺  So your answer is B, \boxed{x.

(Number line is below.)

Hope~this~helps~and,\\Best~of~luck!\\\\~~~~~-TotallyNotTrillex

5 0
2 years ago
Read 2 more answers
How do you solve 4x+2=1/2x+17
DochEvi [55]
1) 4x + 2 = 1/2x + 17
2) 4x - 1/2x = 17 - 2
3) 3.5x = 15
4) (3.5x)/3.5 = 15/ 3.5
5) x = 4.29 (rounded)
4 0
3 years ago
Read 2 more answers
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