Answer:
%P = 8%
the percentage of fat in the mixture is 8%
Step-by-step explanation:
Given;
The percentage of fat in the mixture is;
%P = total mass of fat in mixture/total mass of mixture × 100%
%P = F/T × 100% ….....1
Mass of fat in mixture is;
She purchases 5 pounds of ground beef which is 15% fat
F1 = 15% of 5 pounds = 0.15×5 pounds
F1 = 0.75 pound
and combines it with 7 pounds of ground turkey which is only 3% fat
F2 = 3% of 7 pounds = 0.03 × 7
F2 = 0.21 pound
Total mass F = F1 + F2
F = 0.75+0.21
F = 0.96 pound
Total mass of mixture T = 5 + 7 pounds
T = 12 pounds.
From equation 1,
%P = F/T × 100%
%P = 0.96/12 × 100%
%P = 0.08×100%
%P = 8%
the percentage of fat in the mixture is 8%
Hello!
To find the volume of the water, we would need to use the density formula. The density formula is d = m/V.
In this formula, d is the density, m is the mass and V is the volume.
1. To find the volume of 100 grams of ice, we substitute the appropriate values into the formula and solve for the volume using basic algebra.
0.92g/cm³ = 100g/V (multiply both sides by V)
0.92g/cm³ · V = 100g (divide both sides by 0.92g/cm³)
V = 108.69 cm³.
The volume of 100 grams of ice is about 108.69 cm³.
2. To find the volume of the completely melted ice, we would use the same formula, but the density is now 1.00 g/mL.
1.00g/mL = 100g/V (multiply both sides by V)
1.00g/mL · V = 100g (divide both sides by 1.00g/mL)
V = 100 mL
Therefore, the volume of the melted ice is 100 mL.
<u>Final answers</u>:
- 108.69 g/cm³
- 100 mL
In math (or English, for that matter), a question is never true or false. Only a statement can have such attributes.
If you make the statement "if A ate many sugar, A will get diabetes," in math it cannot be decided wheter it is true or false without additional information about the truth values of the statements "A ate many sugar" and "A will get diabetes".

Distribute 3 throught the parentheses

Move the variable to the left-hand side and change its sign

Move the constant to the right-hand side and change its sign

Collect like terms

Divide both sides of the equation by -3
