If your solving for x, you need to isolate/get the variable "x" by itself in the inequality:
-24 ≤ 3x - 9 First add 9 on both sides
-24 + 9 ≤ 3x - 9 + 9
-15 ≤ 3x Then divide 3 on both sides to get "x" by itself
-5 ≤ x [or x ≥ -5 if you prefer "x" to be on the left side]
Since in a pass code, the placement of the digits is
important, therefore this means that to solve for the total number of
possibilities we have to make use of the principle of Permutation. The formula
for calculating the total number of possibilities using Permutation is given
as:
P = n! / (n – r)!
where,
n = is the total amount of numbers to choose from = 20
r = is the total number of digits needed in the passcode =
4
Therefore solving for the total possibilities P:
P = 20! / (20 – 4)!
P = 20! / 16!
P = 116,280
<span>Hence there are a total of 116,280 possibilities of pass
codes.</span>
Not always but your answer is sometimes
Answer:
1,458,783,255,601
Step-by-step explanation:
(-1,099)^2
Break it apart:
(-1,099)*(-1,099)
Multiply the signs and numbers:
Two negatives make a positive so you are left with just 1,207,801.
Next, you square 1,207,801:
(1,207,801)*(1,207,801)
And you get the number 1,458,783,255,601
