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2 years ago

I need to get rid of 50 points so here you go

Mathematics

2 answers:

user100 [1]2 years ago

7 0

Answer:

thanks

Step-by-step explanation:

than you for the points :)

solniwko [45]2 years ago

4 0

Answer:

Thanks for the points!

Step-by-step explanation:

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SOMOEN DELETED ALL MY ASNWERS NOW I ONLY HAVE 13 POINTS WHY WHY WHYYYYYYYYY

Vedmedyk [2.9K]

Answer:

Maybe its because you give useless answers to get points.

Idiot.

7 0

2 years ago

Help please! Question is in picture

netineya [11]

39 ft of carpet

11x3+3x2=39

3 0

2 years ago

How do you simplify -24e5/6e

kifflom [539]

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hope it helps</span>

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3 years ago

Find the slope-intercept form of the equation of the line that passes through the point P and makes angle with the positive x-

SIZIF [17.4K]

Answer:

The answer is " $y= -x+7$ "

Step-by-step explanation:

If $\bold{\theta = 135^{\circ}}$

point: $p=(2,5)$

Formula:

$\to m= \tan \theta \\\\\to (y-y_1)= m(x-x_1)$

$\to m= \tan \ 135^{\circ} = -1\\\\\to x_1= 2\\\\\to y_1=5$

Put the value in the above formula:

$\to y- 5 = -1(x-2)\\\\\to y- 5 = -x+2\\\\\to x+y = 5+2\\\\\to x+y=7$

$\to y= -x+7$

3 0

2 years ago

Find all points having an x-coordinate of 2 whose distance from the point (-1,-2) is 5

mariarad [96]

$The\ equation\ of\ the\ circle:(x-a)^2+(y-b)^2=r^2\\\\where\ (a;\ b)\ -the\ coordinates\ of\ the\ center;\ r-the\ radius\\-----------------------------\\(-1;-2)-the\ center\ of\ the\ circle\\r=5\\\\The\ equation:(x+1)^2+(y+2)^2=5^5\\\\Put\ x=2\ to\ the\ equation:\\\\(2+1)^2+(y+2)^2=25\\3^2+(y+2)^2=25\\9+(y+2)^2=25\\(y+2)^2=25-9\\(y+2)^2=16\iff y+1=\pm\sqrt{16}\\\\y+1=-4\ or\ y+1=4\ \ \ \ \ |subtract\ 1\ from\ both \sides\\y=-5\ or\ y=3\\\\Answer:(2;-5)\ and\ (2;\ 3).$

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3 years ago