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velikii [3]
3 years ago
12

Y=13x − 1x − 3y = 5 What is the solution to the system of equations shown above? ​​

Mathematics
1 answer:
Soloha48 [4]3 years ago
3 0

Answer:

(5/3,5)

Step-by-step explanation:

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Simplify 5+4x(8-6)^2<br> please help me please hurry please
Fed [463]
5+16x.......................
7 0
4 years ago
After a dreary day of rain, the sun peeks through the clouds and a rainbow forms. You notice the rainbow is the shape of a parab
Gekata [30.6K]

We can answer the first part of the question not taking intersecting function into account. The domain of y=-x^{2}+36 is all the numbers, x∈(-∞, +∞) and the range is y∈(-∞, 36]. We can observe these results with the help of a graph, as well. Since we are talking about the rainbow, the values above the ground level will make sense. In this case, we will take into account the range as it changes between 0 and 36, included and the domain between -6 and 6. Here (0;36) is the y-intercept and (-6;0) and (6;0) are the x-intercepts of the parabola.


Since in our problem, the linear function that intersects parabola is not given, we have to provide it by ourselves according to the conditions of the problem. It could be any line intersecting parabola in two points. One important point is that the y-intercept has to be no more than 36. Considering these conditions, we can set our linear function to be y=0.5x+5. We can observe the points that we included in the table (they have been given with orange dots in the graph and the table is attached below). We can see that the values of the function (values of y) are positive. Indeed, we are discussing the part of the rainbow above the ground level.


The system of equations with linear and quadratic functions has got two solutions and we can observe that result from the graph. The solutions are (-5.823; 2.088) and (5.323; 7.662). The solutions are the intersection points.

7 0
3 years ago
In Vancouver, British Columbia, the probability of rain during a winter day is 0.42, for a spring day is 0.23, for a summer day
nadezda [96]

Answer:

31.82% probability that this day would be a winter day

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening

In this question:

Event A: Rain

Event B: Winter day

Probability of rain:

0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).

So

P(A) = 0.42*0.25 + 0.23*0.25 + 0.16*0.25 + 0.51*0.25 = 0.33

Intersection:

Rain on a winter day, which is 0.42 of 0.25. So

P(A \cap B) = 0.42*0.25 = 0.105

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

P(B|A) = \frac{0.105}{0.33} = 0.3182

31.82% probability that this day would be a winter day

6 0
3 years ago
laura purchased a prepaid phone card for $25 . long distance calls cost 8 cents a minute using this card. laura used her card on
ira [324]
Amount spent on the last call = $25 - $22.04 = $2.96 = 296 cents
Number of minutes used for last call = 296 / 8 = 37 minutes.
6 0
3 years ago
3(y-1)=y-11 plz solve this equation with explaination
stellarik [79]
3(y-1)=y-11

Distribute:
3y - 1 = y- 11

Add 11 to both sides

3y - 12 = y

subtract 3y on both sides

-12 = -2y

Divide by 2y

y= 6
3 0
3 years ago
Read 2 more answers
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