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3 years ago

Please help me with this math problem.

Mathematics

2 answers:

Nina [5.8K]3 years ago

5 0

Answer:

x=25

Step-by-step explanation:

because of vertical angles theorem you set them equal to each other

4x+50=150

subtract 50 from both sides

4x=100

devide by 4 on both sides

x=25

miss Akunina [59]3 years ago

5 0

Answer:

x=25

Step-by-step explanation:

180 degrees is half a circle so you subtract 180 from 150 to get 30, that's for both the missing angles. Then you subtract 180 from 30 to get 150 and set 4x+50=150 then solve.

4x+50=150

4x=100

x=25

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Which table represent a linear function

777dan777 [17]

Answer:

The last answer is correct. (x: 1,2,3,4 ; y: -5,0,5,10)

Step-by-step explanation:

In a linear function, the rate of increase/decrease is constant (the same). For the last answer, since for every x increase, y increases by 5, it is linear and has a constant rate of change.

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2 years ago

The Lacrosse booster club is holding a raffle for a fundraiser. They will sell 100 tickets for $5 each and select 4 winners. All

Nadusha1986 [10]

Answer:

<h2>There are 3,921,225 ways to select the winners.</h2>

Step-by-step explanation:

This problem is about combinations with no repetitions, because the same person can't win four times. It's a combinaction because the order of winning doesn't really matter.

Combinations without repetitions are defined as

$C_{n}^{r} =\frac{n!}{r!(n-r)!}$

Where $n=100$ and $r=4$ .

Replacing values, we have

$C_{100}^{4} =\frac{100!}{4!(100-4)!}=\frac{100!}{4! 96!}=\frac{100 \times 99 \times 98 \times 97 \times 96!}{4! \times 96!}= \frac{94,109,400}{24}= 3,921,225$

Therefore, there are 3,921,225 ways to select the winners.

Additionally, as you can imagine, the probability of winning is extremely low, it would be 3,921,225 to 1.

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3 years ago

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±
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6
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2 years ago

Answer all for brainliest

Marizza181 [45]

Answer:

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Step-by-step explanation:

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2 years ago

I need help please Asap

s2008m [1.1K]

Answer:

Step-by-step explanation:

Equation one:

x = -5, x = -1 (Both are real)

Equation two:

No real solutions

Equation three:

x = -3 (Real)

Equation four:

No real solutions

The easiest way to figure out if an equation has real solutions is to factor it. If it is factorable, then it has real solutions. If it isn't, then it doesn't have real solutions.

4 0

1 year ago