Dang...H0: μ = 115
HA: μ ≠ 115
Sample mean = 120
Standard deviation = 25
Standard error of mean = σ / √ n
Standard error of mean = 25 / √ 100
SE = 25/10
Standard error of mean 2.5
z = (xbar- μ ) / SE
z = (120-115) / 2.5
z = 2
p-value = 2 P( z > 2) = 2(0.0228) = 0.0456
the data are statistically significant at level = .05, but not at level = .01.
2)
H0: μ = 115
HA: μ ≠ 115
Sample mean = 119
Standard deviation = 25
Standard error of mean = σ / √ n
Standard error of mean = 25 / √ 100
SE = 25/10
Standard error of mean 2.5
z = (xbar- μ ) / SE
z = (119-115) / 2.5
z = 1.6
p-value = 2P( z > 1.6) = 2(0.0548) =0.1096
3)
a statement about the population the researcher suspects is true, and is trying to find evidence for.
4)
Sample mean = 80
Standard deviation = 20
Standard error of mean = σ / √ n
Standard error of mean = 20 / √ 100
SE = 20/10
The Standard error of mean 2
Confidence interval 80-(2)(1.645)
and 80+(2)(1.645)
(76.7, 83.3)
Answer:
21
Step-by-step explanation:
Given the following expressions
f(x) = x³-2x
g(x) =-x-2
We are to find (fog)(-5)
fog = f(g(x))
f(g(x)) = f(-x-2)
Replace x with -x-2 in f(x)
f(-x-2) = (-x-2)³-2(-x-2)
f(-x-2) = (-x-2)³+2x+4
fog = (-x-2)³+2x+4
Substitute x = -5 into the result
fog(-5) = (-x-2)³+2x+4
fog(-5) = (-(-5)-2)³+2(-5)+4
fog(-5) = (5-2)³-10+4
fog(-5) = 3³-6
fog(-5) = 27-6
fog(-5) = 21
Hence the required result of the composite function is 21
Answer:
THAT AINT COLLEGE WORK THAT EZ AS. trust
Step-by-step explanation:
The answer is C.
To solve these types of equations you first need to make sure that you equation is equal to 0. In this case all of the numbers are already on the same side so no work needs to be done there. Then we can get a, b and c values for the quadratic equation by looking at the coefficients.
a = 4 (number attached to x^2)
b = -6 (number attached to x)
c = 1 (number with no variable attached)
Now we can put this into the quadratic equation.

