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4 years ago

Which equation demonstrates the additive identity property?

Mathematics

1 answer:

boyakko [2]4 years ago

3 0

the answer for the question is b! :)

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Prove the identity 2csc2x=csc^2xtanz

Verizon [17]

Step-by-step explanation:

Consider the LHS, after the 5th step, consider the RHS

$2 \csc(2x) = \csc {}^{2} (x) \tan(x)$

$2 \frac{1}{ \sin(2x) } = \csc {}^{2} (x) \tan(x)$

$2 \times \frac{1}{2 \sin(x) \cos(x) } = \csc {}^{2} (x) \tan(x)$

$\frac{1}{ \sin(x) \cos(x) } = \csc {}^{2} (x) \tan(x)$

$\csc(x) \sec(x) = \csc {}^{2} (x) \tan(x)$

Consider the RHS

$\csc(x) \sec(x) =( 1 + \cot {}^{2} (x) ( \tan(x))$

$\csc(x) \sec(x) = \tan(x) + \cot(x)$

$\csc(x) \sec(x) = \frac{ \sin(x) }{ \cos(x) } + \frac{ \cos(x) }{ \sin(x) }$

$\csc(x) \sec(x) = \frac{1}{ \sin(x) \cos(x) }$

$\csc(x) \sec(x) = \csc(x) \sec(x)$

7 0

2 years ago

Examine the two similar triangles below solve for y need by 11:59 for final exam

Sloan [31]

Answer:

Step-by-step explanation:

dont listen to me this is a wrong answer

8 0

3 years ago

Solve for x.<br> y = (5+x}m<br> Answer?

Tanzania [10]

Answer:

x=ym−4

Step-by-step explanation:

y=(4+x)m

Here we have one equation with three unknowns. This cannot be "solved". We can only express one variable in terms of the other two.

Let's isolate x.

Divide through by m

ym=4+x

x=ym−4

(I really hope this helps)

4 0

3 years ago

The length of a chord is equal to its distance to the center of the circle. A second chord in the same circle is twice as long a

Rama09 [41]

Answer:

The distance from the center of the circle to the longer chord is twice smaller than the distance from the center to the shorter chord.

Step-by-step explanation:

The length of the chord AB is the same as the distance OC from the center to the cord. Let OC=2x, then CA=x. By the Pythagorean theorem, the radius r of the circle is

$r^2=OC^2+AC^2,\\ \\r^2=(2x)^2+x^2=5x^2,\\ \\r=\sqrt{5}x.$

The length of the arc ED is 4x.

Consider right triangle EFO. In this triangle, EF=2x, EO=r, then the distance OF is

$OF^2=OE^2-EF^2,\\ \\OF^2=5x^2-(2x)^2=x^2,\\ \\OF=x.$

The distance from the center of the circle to the longer chord is twice smaller than the distance from the center to the shorter chord.

5 0

4 years ago

Two students in your class, Hunter and Maggie, are disputing a function. Hunter says that for the function, between x = −2 and x

dangina [55]

So basically, if it goes up then back down to the same level, the change is 0 since it is like, running 100 feet west, then running 100 feet east, you are at your original spot, your positino did not change

maggie is explaing what hunter is saying

7 0

3 years ago

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