Question

there are 14 NBA teams who do not make the playoffs of these teams 3 of them will be randomly selected to make the 1st, 2nd, and 3rd pick. how many different ways can the 1st-3rd pick be arranged

Answer 1

Answer:

In 2184 different ways can the 1st-3rd pick be arranged.

Step-by-step explanation:

We are given the Total number of NBA teams does not make the play offs = 14

We need to find number of ways in which 3 teams randomly picked.

We use permutation to find the number of ways.

We know that number of ways of selecting r item from n different item is equal to $^nP_r\:\:=\:\:\frac{n!}{(n-r)!}$

Here, r = 3 and n = 14

$\implies^{14}P_3=\frac{14!}{(14-3)!}frac{14!}{11!}=frac{14\times13\times12\times11!}{11!}=14\times13\times12=2184$

Therefore, In 2184 different ways can the 1st-3rd pick be arranged.

Answer 2

The 1-3 picks could be arranged almost 25 different times