1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vovikov84 [41]
2 years ago
15

8 pencils for 14 dollars

Mathematics
2 answers:
lapo4ka [179]2 years ago
5 0

Answer:

$1.75 for each pencil.

Step-by-step explanation:

if you're asking the price for each pencil then its 1,75 for each because 8 multiplied by 1.75 is 14 :))

Schach [20]2 years ago
4 0

Answer:

1 pencil will be for 1.75 $

You might be interested in
What is 200/30 in a mixed number
mixer [17]
6 20/30

hope it helps
7 0
3 years ago
Someone Help I will give Branlist for whoever answers first!!!
Assoli18 [71]

Answer:

A its like, getting a plate before you make a sandwich, you have to get a plate first, or else you can't start making your sandwich.

Step-by-step explanation:

you don't have to give brainliest, im just helping lol

6 0
2 years ago
Read 2 more answers
W = 1/2QV if w=.47 and v=13.5
Mrac [35]
If w is .47 and v is 13.5 then, 0.47=6.75Q
8 0
3 years ago
Multiply the polynomials.
slavikrds [6]
<span>(x + 3)(x² – 6x + 5)= x³-6x²+5x+3x²-18x+15 =x³ -3x²-13x+15 Answer B</span>
4 0
2 years ago
Read 2 more answers
Given f(x) = 4x^4 find f^-1(x) Then state whether f^-1(x) is a function.
sdas [7]

Answer:

  • f^{-1}(x)=\pm\sqrt[4]{\dfrac{x}{4}}
  • f^{-1}(x) \quad\text{is not a function}

Step-by-step explanation:

To find the inverse function, solve for y:

x=f(y)\\\\x=4y^4\\\\\dfrac{x}{4}=y^4\\\\\pm\sqrt[4]{\dfrac{x}{4}}=y\\\\f^{-1}(x)=\pm\sqrt[4]{\dfrac{x}{4}}

f(x) is an even function, so f(-x) = f(x). Then the inverse relation is double-valued: for any given y, there can be either of two x-values that will give that result.

___

A function is single-valued. That means any given domain value maps to exactly one range value. The test of this is the "vertical line test." If a vertical line intersects the graph in more than one point, then that x-value maps to more than one y-value.

The horizontal line test is similar. It is used to determine whether a function has an inverse function. If a horizontal line intersects the graph in more than one place, the inverse relation is not a function.

__

Since the inverse relation for the given f(x) maps every x to two y-values, it is not a function. You can also tell this by the fact that f(x) is an even function, so does not pass the horizontal line test. When f(x) doesn't pass the horizontal line test, f^-1(x) cannot pass the vertical line test.

_____

The attached graph shows the inverse relation (called f₁(x)). It also shows a vertical line intersecting that graph in more than one place.

5 0
2 years ago
Other questions:
  • The table shows different ways that Cameron can display his 12 model cars on the shelves how many shelves will display 2 cars if
    13·1 answer
  • In right triangle ABC, AB = 10, AC = 6 and BC = 8 units. What is the distance from C to the midpoint of segment AB?
    11·2 answers
  • Write the linear function in slope-intercept form given the slope and a point.
    14·1 answer
  • Which of these is not included in the set of rational numbers?
    15·2 answers
  • What is another solution of the equation x+7=y
    12·1 answer
  • A car is driven 600 miles and uses 20 gallons of gas. If gas is $1.05 per gallon, what is the gasoline cost per mile?
    6·1 answer
  • At midnight, the temperature in a city was 5 degrees Celsius. The temperature was dropping at a steady rate of 2 degrees Celsius
    6·1 answer
  • Factor yz + 6 + y +6z.<br> z + 1)(y + 6)<br> (z - 1)(y + 6)<br> (z + 6)(y - 1)
    15·1 answer
  • WILL MARK BRAINLIEST!! PLEASE HELP ME
    11·1 answer
  • Please don’t copy and paste the answer from another Brainly, if I asked this question again is because the answers I read weren’
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!