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3 years ago

Find the mean, median, and mode(s) of the data. 4, 6, 5, 4, 4, 5, 4, 8

Mathematics

1 answer:

Mumz [18]3 years ago

7 0

Answer:

[see below]

Step-by-step explanation:

Add all values together:

$4+6+5+4+4+5+4+8 = 40$

There are 8 numbers in the data set.

40 ÷ 8 = 5

The mean of the data is 5.

<h3>The Median:</h3>

Order the numbers in ascending order.

4, 4, 4, 4, 5, 5, 6, 8

There is no exact middle number.

$(4+5)/2 =4.5$

The median of the data is 4.5.

'4' appears the most in the data set.

4, 4, 4, 4, 5, 5, 6, 8

The mode of the data is 4.

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What is the rule to these ordered pairs

Anton [14]

The digits on the right side are half the value on the left ones

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3 years ago

Read 2 more answers

2x+y = - 3<br> X + 3y = 6<br> Solve the system of equations by graphing

Anna71 [15]

Answer:

(3/5, 9/5)

Step-by-step explanation:

Here's the graph :)

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3 years ago

The amounts below represent the last twelve transactions made to Juan's checking account.Positive numbers represent deposits and

TiliK225 [7]

Answer:

Option B. Range of the given sample data is 113.

Step-by-step explanation:

The given question is incomplete; here is the complete question.

Find the range for the given sample data.

The amounts below represent the last twelve transactions made to Juan's checking account. Positive numbers represent deposits and negative numbers represent debits from his account.

$28 -$20 $67 -$22 -$15 $17 -$38 $41 $53 -$13 $30 $75

Option A. $75

Option B. $113

Option C. $37

Option D. -$113

Transaction done by Juan can be arrange from lowest to highest

-38 -22 -20 - 15 -13 17 28 30 41 53 67 75

Now we know rage of the sample data = Highest value - Lowest value

= 75 - (-38)

= 113

Therefore, range of the given sample data is 113.

Option B is the answer.

6 0

3 years ago

I really need help here ASAP

AlexFokin [52]

Answer:

D. $x=\frac{-4-\sqrt{31}}{3}$ or $x=\frac{-4+\sqrt{31}}{3}$

Step-by-step explanation:

The given equation is:

$3x^2+8x=5$

Divide through by 3;

$x^2+\frac{8}{3}x=\frac{5}{3}$

Add the square of half the coefficient of x to both sides.

$x^2+\frac{8}{3}x+(\frac{4}{3})^2=\frac{5}{3}++(\frac{4}{3})^2$

$x^2+\frac{8}{3}x+\frac{16}{9}=\frac{5}{3}+\frac{16}{9}$

The left hand side is now a perfect square:

$(x+\frac{4}{3})^2=\frac{31}{9}$

Take square root

$x+\frac{4}{3}=\pm \sqrt{ \frac{31}{9}}$

$x=-\frac{4}{3}\pm \sqrt{ \frac{31}{9}}$

$x=-\frac{4}{3}\pm \frac{\sqrt{31}}{3}$

D. $x=\frac{-4-\sqrt{31}}{3}$ or $x=\frac{-4+\sqrt{31}}{3}$

5 0

3 years ago

Find the determinant of the matrix.

Natalka [10]

Answer:

Step-by-step explanation:

$\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] = ad-bc$

0(4)-4(0) = 0

8 0

3 years ago