All categories

4 years ago

Find the mean, median, and mode(s) of the data. 4, 6, 5, 4, 4, 5, 4, 8

Mathematics

1 answer:

Mumz [18]4 years ago

7 0

Answer:

[see below]

Step-by-step explanation:

Add all values together:

$4+6+5+4+4+5+4+8 = 40$

There are 8 numbers in the data set.

40 ÷ 8 = 5

The mean of the data is 5.

<h3>The Median:</h3>

Order the numbers in ascending order.

4, 4, 4, 4, 5, 5, 6, 8

There is no exact middle number.

$(4+5)/2 =4.5$

The median of the data is 4.5.

'4' appears the most in the data set.

4, 4, 4, 4, 5, 5, 6, 8

The mode of the data is 4.

You might be interested in

Which statement about the system of equations is true?

vagabundo [1.1K]

8x + 6y = 10 ----------- (1)
5x - 3y = 2.2 ---------- (2)

(2) x 2:
10 x - 6y = 4.4 --------(2a)

(2a) + (1)
18x = 14.4
x = 1.8 ------- sub into (1)
8 (1.8) + 6y = 10
14.4 + 6y = 10
6y = 10 - 14.4
6y = - 4.4
y = - 0.73

There is 1 set of solution to it. (Answer C)

3 0

3 years ago

What is the slope of the line with the equation<br>y = -3x + 4

mixer [17]

Answer:

The slope is -3

Step-by-step explanation:

The equation is in y=mx+b form where m is always the slope. In this case, m=-3, therefore that is the slope

8 0

4 years ago

Read 2 more answers

A square acre of land is 4,840 square yards. The length of one side of the square is between which of the following?

maks197457 [2]

Hi there!

If we know the area is a square, we can use the formula for the area of a square to figure out what one side would be between. Knowing the value allows us to determine what it would be between. In this case, it is between 69 and 70.

WORK:
squareroot(4840) = 69.6

ANSWER:
Option B - 69 yd and 70 yd

6 0

4 years ago

Conrad spent $48 on art supplies. The canvas for each of his paintings is an additional $2. He plans to sell his paintings for $

Gnom [1K]

I’m sorry I didn’t mean to tell 6

6 0

4 years ago

Find condition that zeros of polynomial p(x)=ax2+bx+c are reciprocal of each other

snow_lady [41]

Suppose $p(x)=ax^2+bx+c$ has two roots, reciprocals of one another. Call them $r_1,r_2$ , with $r_2=\dfrac1{r_1}$ .

Let's divide through $p(x)$ by $a$ for now. By the fundamental theorem of algebra, we can factorize $p(x)$ as

$x^2+\dfrac ba x+\dfrac ca=(x-r_1)(x-r_2)=(x-r_1)\left(x-\dfrac1{r_1}\right)$

Expand the RHS to get

$x^2-\left(r_1+\dfrac1{r_1}\right)x+1$

so we must have

$-\dfrac ba=r_1+\dfrac1{r_1}$
$\dfrac ca=1$

The first equation says $a$ and $b$ occur in a ratio of the negative sum of the roots of $p(x)$ , while the third equation says that the first and last coefficients $a,c$ must be the same.

5 0

3 years ago