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saw5 [17]
3 years ago
11

Need help with question 40!!!!

Mathematics
1 answer:
kompoz [17]3 years ago
4 0

Answer:

0.84

Step-by-step explanation:

You got number 38 wrong. It should be 0.625

So number 39's answer should be the code.

0.84

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In the system of equations, r and s are constants. If the system has infinitely many solutions, what is the value of rs?
exis [7]

Answer:  B) -48

Step-by-step explanation:

If the system of two linear equations a_1x+b_1y=c_1\ \&\ a_2+b_2y=c_2 has infinitely many solutions , then

\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}=k

For the given system of linear equations : rx-sy=26\\4x+3y=13

We , will have

\dfrac{r}{4}=\dfrac{-s}{3}=\dfrac{26}{13}=2\\\\\Rightarrow\ r= 4\times2=8\ \ \&\ \ s=2\times-3=-6

The value of rs=(8)\times-6=-48

Hence, the value of rs is -48.

Thus , the correct option is B) -48.

6 0
3 years ago
Solve this <br> <img src="https://tex.z-dn.net/?f=4%5Cleft%285x-2%5Cright%29%3D2%5Cleft%289x%2B3%5Cright%29" id="TexFormula1" ti
vampirchik [111]

Answer:

  • Solution of equation ( x ) = <u>7</u>

Step-by-step explanation:

In this question we have given with an equation that is <u>4</u><u> </u><u>(</u><u> </u><u>5</u><u>x</u><u> </u><u>-</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>(</u><u> </u><u>9</u><u>x</u><u> </u><u>+</u><u> </u><u>3 </u><u>)</u><u>.</u> And we are asked to solve this equation that means we have to find the value of <u>x</u><u>.</u><u> </u>

<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>

<u>\quad \longrightarrow \: 4 ( 5x - 2 ) = 2 ( 9x + 3 )</u>

<u>Step </u><u>1</u><u> </u><u>:</u> Removing parenthesis :

\quad \longrightarrow \:20x - 8 = 18x + 6

<u>Step </u><u>2</u><u> </u><u>:</u> Adding 8 from both sides :

\quad \longrightarrow \:20x - \cancel{ 8 }+  \cancel{8} = 18x + 6 + 8

On further calculations we get :

\quad \longrightarrow \:20x = 18x + 14

<u>Step </u><u>3 </u><u>:</u> Subtracting 18 from both sides :

\quad \longrightarrow \:20x - 18x =  \cancel{18x }+ 14 -  \cancel{18}

On further calculations we get :

\quad \longrightarrow \:2x = 14

<u>Step </u><u>4</u><u> </u><u>:</u> Dividing with 2 on both sides :

\quad \longrightarrow \: \frac{ \cancel{ 2}x}{ \cancel{2}}  =   \cancel{\frac{14}{2} }

On further calculations we get :

\quad \longrightarrow \:  \blue{\boxed{ \frak{x = 7}}}

  • <u>Therefore</u><u>,</u><u> </u><u>solution</u><u> </u><u>of </u><u>this </u><u>equation</u><u> </u><u>is </u><u>7</u><u> </u><u>or </u><u>we </u><u>can </u><u>say </u><u>that </u><u>value </u><u>of </u><u>this </u><u>equation</u><u> </u><u>is </u><u>7</u><u> </u><u>.</u>

<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>

We are verifying our answer by substituting value of x in given equation. So ,

  • 4 ( 5x - 2 ) = 2 ( 9x + 3 )

  • 4 [ 5 ( 7 ) - 2 ] = 2 [ 9 ( 7 ) + 3 ]

  • 4 ( 35 - 2 ) = 2 ( 63 + 3 )

  • 4 ( 33 ) = 2 ( 66 )

  • 132 = 132

  • L.H.S = R.H.S

  • Hence, Verified.

<u>Therefore</u><u>,</u><u> </u><u>our </u><u>value</u><u> for</u><u> x</u><u> is</u><u> </u><u>correct </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
4 0
2 years ago
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Simplify the ratio 11/33 and then give 2 more equivalent ratios
KATRIN_1 [288]
The simplest ratio is 1/3. Equivalent ratios would be 3/9 and 5/15.
4 0
3 years ago
What is the solution for the system of equations {9x+8y=3 6x−12y=−11?
lions [1.4K]

Answer:

( - \frac{1}{3}, \frac{3}{4} )

Step-by-step explanation:

Given the 2 equations

9x + 8y = 3 → (1)

6x - 12y = - 11 → (2)

To eliminate the y- term multiply (1) by 1.5

13.5x + 12y = 4.5 → (3)

Add (2) and (3) term by term

(6x + 13.5x) + (- 12y + 12y) = (- 11 + 4.5)

19.5x = - 6.5 ( divide both sides by 19.5 )

x = \frac{-6.5}{19.5} = - \frac{1}{3}

Substitute this value into either of the 2 equations and solve for y

Using (1), then

- 3 + 8y = 3 ( add 3 to both sides )

8y = 6 ( divide both sides by 8 )

y = \frac{6}{8} = \frac{3}{4}

Solution is (- \frac{1}{3}, \frac{3}{4} )

6 0
3 years ago
6-8x=7-9x+12<br> solve for x
damaskus [11]
The answer is 69,420
5 0
3 years ago
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