1. Wind speed and direction respond to pressure gradient forces that exist between high and low pressure areas. In the Northern Hemisphere and because of the rotation of the earth, winds circulate in a clockwise fashion around areas of high pressure and in a counter-clockwise manner around regions of lower pressure. Air pressure decreases relatively slowly with height in regions dominated by warm air and relatively rapidly with height in areas where cold air prevails. As a result, wind patterns in the upper atmosphere tend to flow in an oscillating manner around major pockets of warm and cold air.
<span>Horizontal pressure gradient force- results from the high and low pressure systems (highs, lows, troughs and ridges) in the atmosphere. Air tends to move air from regions of high pressure to regions of low pressure.
</span>Friction- the drag on the air by the earth's surface (e.g., plants, trees, buildings, mountains, etc.).
Friction always acts opposite to air motion
<span>Coriolis Force<span>Coriolis force- the force that results from Earth's rotation.The Coriolis force solely results from living on a rotating object -- Earth. It acts only on objects moving with respect to the earth's surfaceCentrifugal force- the tendency for a body to resist a change in direction.
<span>
</span></span></span>2. The amount of sunlight striking an air mass influences its temperature. As the air heats up, it rises in the air column and begins sucking cool air in behind it. This causes the winds that drive much of the planet’s weather systems.
The weather is also affected by the local geography. For example, mountains often block winds and rainfall. This causes one side of the mountain to have very high amounts of rainfall and lush vegetation, while the far side of the mountains remain very dry and desolate.
The air pressure in an area can impede or encourage the flow of weather systems. In general, air masses flow from areas of high pressure towards areas of low pressure. Usually, storms occur in areas of extremely low pressure.
The amount of water in the atmosphere affects the local humidity and rainfall. Air masses that move across bodies of water often draw water up into the air before depositing it somewhere else as rain, snow or sleet
Answer:
The perimeter of the polygon = 18 units
The area of the polygon will be 
square units
Step-by-step explanation:
<u><em>Computing the Perimeter of the Polygon: </em></u>
Considering the polygon with vertices
As the polygon is drawn in coordinate plane as shown in figure a.
From the attached figure a, we can observe that
- The length of the side
units
- The length of the side
units
- The length of the side
units
- The length of the side
units
So, the perimeter of the polygon can be calculated by taking the sum of the lengths of all sides i.e.
The perimeter of the polygon = 
= 3 + 6 + 6 + 3
= 18 units
<u><em>Computing the Area of the Polygon: </em></u>
Area can be calculated by multiplying the length and width of the polygon.
So, the area will be:
Therefore, the area of the polygon will be square units
Keywords: area, perimeter, polygon
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Answer:
Step-by-step explanation:
6400(1+i)³=8334
(1+i)³=1.3021875
∛(1+i)³=∛(1.3021875)
1+i= 1.092
i= .092
I guess if you were to round to 1 decimal point it'd be .1
Hence it is a simply rearrangement of the equation to start with, in order to make the subject:
This is the graph in 'slope-intercept' form. From here it is easy to see that gradient = and that y-intercept = 490.
The easiest way to draw a straight-line graph, such as this one, is to plot the y-intercept, in this case (0, 490), then plot another point either side of it at a fair distance (for example substitute = -5 and = 5 to procure two more sets of co-ordinates). These can be joined up with a straight line to form a section of the graph, which would otherwise extend infinitely either side - use the specified range in the question for x-values, and do not exceed it (clearly here the limit of -values is 0 ≤ x ≤ 735, since neither x nor y can be negative within the context of the question - the upper limit was found by substituting = 0).
In function notation, the graph is:
The graph of this function represents how the value of the function varies as the value of x varies. Looking back at the question context, this graph specifically represents how many wraps could have been sold at each number of sandwich sales, in order to maintain the same profit of $1470.
When the profit is higher, the gradient is not changed (this is defined by the relationship between the $2 and $3 prices, not the overall profit) - instead the -intercept is higher:
Therefore we have gleaned that the new y-intercept is.
Clearly I cannot see the third straight line. However the method for finding the equation of a straight line graph is fairly simple:
1. Select two points on the line and write down their coordinates
2. The gradient of the line =
3. Find the change in (Δ
4. Find the change in (Δ
5. Divide the result of stage 3 by the result of stage 4
6. This is your gradient
7. Take one of your sets of coordinates, and arrange them in the form , where your is the gradient you just calculated
8. There is only one variable left, which is (the y-intercept). Simply solve for this
9. Now generalise the equation, in the form , by inputting your gradient and y-intercept whilst leaving the coordinates as and
For example if the two points were (1, 9) and (4, 6):
Δ = 6 - 9 = -3
Δ = 4 - 1 = 3
= = -1
I choose the point (4, 6)
6 = (-1 * 4) + c
6 = c - 4
c = 10
Therefore, generally,
Within the context of the question, I imagine the prices of the two lunch specials will be the same in the third month and hence the gradient will still be - this means steps 1-6 can be omitted. Furthermore if the axes are clearly labelled, you may even be able to just read off the y-intercept and hence dispose with steps 1-8!
