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Masja [62]
4 years ago
7

You roll a red die, a yellow die, a blue die, and a green die. What is the size of the sample space of all possible outcomes of

rolling these four dice?
Mathematics
1 answer:
VARVARA [1.3K]4 years ago
4 0

Answer:

216 outcomes for the sample space. (c)

Step-by-step explanation:


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I need help and its about Absolute value!!!
Naya [18.7K]
I believe the answer would be 0 because -0 isn’t really a think so 0 would be the only solution
7 0
3 years ago
Use mental math to decide which equations are true. Drag the true equations into the box.
AleksAgata [21]

1.23÷10 = 0.123 is a true statement

Given the expression 1.23÷10, we need to<u> check if the expression is equal to 0.123</u>

<h3>Fractions</h3>

Fractions is a ratio of two integers a/b

Given

  • 1.23÷10

Convert the decimal to a fraction as shown:

  • 1.23 = 123/100

The expression becomes:

  • 123/100 ÷10

= 123/100 * 1/10

=  123/1000

Convert back to decimal

1.23÷10 = 0.123

This shows that 1.23÷10 = 0.123 is a true statement

Learn more on division here: brainly.com/question/12957834

3 0
2 years ago
Bad weather stopped a cricket game for 35 minutes of a schedule 3 1/5 hour match. What percentage of the schedule time was lost?
baherus [9]

Answer:

35 mins lost

out of 3 and 1/2 hrs = 3.5 x 60 mins = 210 mins

%time lost = time lost/total time x 100

= 35/210 x 100

= 1/6 x 100

= 16.66666 %

6 0
3 years ago
19 = X -6
Readme [11.4K]
It pretty sure it would be X=25
3 0
3 years ago
Tina, Sijil, Kia, vinayash Alisha and shifa are playing game by forming two teams. Three players in each team how many different
IgorC [24]

Answer:

20

Step-by-step explanation:

GIVEN: Tina, Sijil, Kia, vinayash Alisha and shifa are playing game by forming two teams Three players in each team.

TO FIND: how many different ways can they be put into two teams of three players.

SOLUTION:

Total number of players =6

total teams to be formed =2

total players in one team =3

we have to number of ways of selecting 3 players for one team, rest 3 will go in other team.

Total number of ways of selecting 3 players =^6C_3

                                                                      =\frac{6!}{3!3!}

                                                                     =20

Hence total number of different ways in which they can be put into two different teams is 6

5 0
4 years ago
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