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Masja [62]
3 years ago
7

You roll a red die, a yellow die, a blue die, and a green die. What is the size of the sample space of all possible outcomes of

rolling these four dice?
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
4 0

Answer:

216 outcomes for the sample space. (c)

Step-by-step explanation:


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Find the length of YZ
emmainna [20.7K]
Larger triangle’s base length

a^2 + b^2 = c^2
a^2 + 3^2 = 8^2
a^2 = 8^2 - (3^2)
sqrt(a^2) = sqrt(55)
a = sqrt(55)
__________________

Smaller triangle’s base length:

The same formula applies.
a^2 + 3^2 = 5^2
a^2 = 5^2 - (3^2)
sqrt(a^2) = sqrt(16)
a = 4
____________

The finale!

Add the two side lengths of a, which is sqrt(55) + 4 (exact answer)
or... 11.416 (unrounded to thousandths place)

Good luck to you!
5 0
3 years ago
What is 4.153 rounded to the nearest tenth?
Dmitry_Shevchenko [17]

The answer is 4.2. Have a good day

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3 years ago
Read 2 more answers
What is the axis of symmetry of a parabola if its x-intercepts are -3 and 5?
ollegr [7]

Answer:

The axis of symmetry will be at 1

Step-by-step explanation:

The middle of -3 and 5 will be the axis :)

-3, -2, -1, 0, 1, 2, 3, 4, 5

-2, -1, 0, 1, 2, 3, 4

-1, 0, 1, 2, 3

0, 1, 2

1

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3 years ago
If orange cost 12.50 pesos each how much do three dozen oranges cost​
GalinKa [24]

Answer:

i guess the answer is 450.

3 0
2 years ago
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
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