The commutative property of addition means the order of the addends doesn't matter; we get the same sum. In symbols
<span>11 + 7 = 7 + 11, choice B, is a good illustration of commutativity.
The next part asks us to use the commutative property. Looking at the choices, we see it's not the commutative property of addition we're to use, it's the commutative property of multiplication. Let's write that generally first:
</span>
Applying that, <span>(4 + 7) * 3 = 3*(4+7), again choice B.
</span>
Answer:
x = -4
Step-by-step explanation:
Solve for x:
3 x - 5 x + 2 = 10
Grouping like terms, 3 x - 5 x + 2 = 2 + (3 x - 5 x):
2 + (3 x - 5 x) = 10
3 x - 5 x = -2 x:
-2 x + 2 = 10
Subtract 2 from both sides:
(2 - 2) - 2 x = 10 - 2
2 - 2 = 0:
-2 x = 10 - 2
10 - 2 = 8:
-2 x = 8
Divide both sides of -2 x = 8 by -2:
(-2 x)/(-2) = 8/(-2)
(-2)/(-2) = 1:
x = 8/(-2)
The gcd of 8 and -2 is 2, so 8/(-2) = (2×4)/(2 (-1)) = 2/2×4/(-1) = 4/(-1):
x = 4/(-1)
Multiply numerator and denominator of 4/(-1) by -1:
Answer: x = -4
Answer:
$18,630
Step-by-step explanation:
The cost of every college is expected to increase 3.5% next year.
The cost to attend Westish College is currently $18000.
What is the expected cost to attend Westish College next year?
The increase in the cost for next year is calculated as:
3.5 % × Current cost
= 3.5% × $18,000
= $630.
The expected cost to attend Westish college next year=
$18,000 + $630
= $18,630
It can't be factorized it has no common factors no factor of 4 will go easily into 9
Answer:
Step-by-step explanation:
Recall that a <em>probability mass function</em> defined on a discrete random variable X is just a function that gives the probability that the random variable equals a certain value k
In this case we have the event
“The computer will ask for a roll to the left when a roll to the right is appropriate” with a probability of 0.003.
Then we have 2 possible events, either the computer is right or not.
Since we have 4 computers in parallel, the situation could be modeled with a binomial distribution and the probability mass function
This gives the probability that k computers are wrong at the same time.
