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lukranit [14]
4 years ago
6

A sports club needs to raise at least $500 by selling chocolate bars for $2.50 each. Sebastian wants to know how many chocolate

bars, c, the sports club must sell in order to reach its goal. Which of the following must be true about the inequality and the resulting graph?
Mathematics
2 answers:
Mice21 [21]4 years ago
6 0

they must sell at least  200 choc bars

c=choc bars

2.5c>or=500

divide both sides by 2.5

c>or=200

Reil [10]4 years ago
4 0

Answer:

80 to right

Step-by-step explanation:

I did the Quiz on Edge that is the answer

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Which number comes next in this series? 1/64, 1/32, 1/16, 1/8, 1/4, 1/2, ?
alexgriva [62]
This is a geometric sequence, with the first term: 1/64

The common ratio is found through the ratio of the first two terms and the second and third term.
\frac{\frac{1}{32}}{\frac{1}{64}} = \frac{\frac{1}{16}}{\frac{1}{32}}
\frac{1}{32} \cdot 64 = \frac{1}{16} \cdot 32

Since there is a common difference of 2, we can generalise this sequence to find the nth term:
T_n = ar^{n-1}
a is the first term, r is the common ratio, and n is the nth term in the sequence.

T_n = \frac{1}{64} \cdot 2^{n-1}
Substituting n = 7, we get:
T_7 = \frac{1}{64} \cdot 2^{7 - 1}
T_7 = \frac{1}{64} \cdot 64
T_7 = \frac{64}{64} = 1

Thus, the next term in the sequence is 1.
6 0
3 years ago
Which does not represent the set shown on this number line?
jeyben [28]
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4 0
3 years ago
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devlian [24]
A. multiply all the numbers together to find the possible outcomes

4 x 4 = 16

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4 x 3 = 12

12/16 = 0.75, or a 75% chance they will not be the same color


hope this helps
6 0
3 years ago
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What is the radius of a circle whose equation is x2 y2 8x – 6y 21 = 0?
andrew11 [14]

we know that

the standard form of the equation of the circle is

(x-h)^{2} +(y-k)^{2}=r^{2}

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

x^{2} +y^{2} +8x-6y+21=0

<u>Convert to standard form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}+8x) +(y^{2}-6y)=-21

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

(x^{2}+8x+16) +(y^{2}-6y+9)=-21+16+9

(x^{2}+8x+16) +(y^{2}-6y+9)=4

Rewrite as perfect squares

(x+4)^{2} +(y-3)^{2}=4

(x+4)^{2} +(y-3)^{2}=2^{2}

the center of the circle is (-4,3)

the radius of the circle is 2\ units

therefore

<u>the answer is</u>

the radius of the circle is 2\ units


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