The probability that cards are from different suits is ![\frac{39}{51}](https://tex.z-dn.net/?f=%5Cfrac%7B39%7D%7B51%7D)
Probability of an event E represented by P(E) can be defined as (The number of favorable outcomes )/(Total number of outcomes).
There are 4 suits hearts, diamonds, club and spade in a standard deck of 52 cards.
Each of them has 13 cards each .
So when we pick first card from a single suit
we can pick it in 13 ways , now 12 cards are left.
We can pick the 2nd card from the same suit in 12 different ways .
So to pick 2 cards from a single suit we have 13x12 ways.
to pick 2 card from 4 suits = 4x13x12=624 ways
Total ways of choosing 2 cards from the pack of 52 cards is 52 X 51 =2652
probability that the cards are of same suits=![\frac{624}{2652} =\frac{12}{51}](https://tex.z-dn.net/?f=%5Cfrac%7B624%7D%7B2652%7D%20%3D%5Cfrac%7B12%7D%7B51%7D)
probability that the cards are of different suits=![1-\frac{12}{51} =\frac{39}{51}](https://tex.z-dn.net/?f=1-%5Cfrac%7B12%7D%7B51%7D%20%3D%5Cfrac%7B39%7D%7B51%7D)
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