I don’t understand the question.
Answer:
896
Step-by-step explanation:
Let's talk first about how many 3 digit numbers there are. The first 3 digit number is 100 and the last is 999. So there are 999-100+1 numbers that are 3 digits long. That simplifies to 900.
Now let's find how many of those have a sum for the digits being 1, then 2 ? Then take that sum away from the 900 to see how many 3 digit numbers have the sum of their digits being more than 2.
3 digit numbers with sum of 1:
The first and only number is 100 since 1+0+0=1.
We can't include 010 or 001 because these aren't really three digits long.
3 digit numbers with sum of 2:
The first number is 101 since 1+0+1=2.
The second number is 110 since 1+1+0=2.
The third number is 200 since 2+0+0=2.
That's the last of those. We could only use 0,1, and 2 here.... Anything with a 3 in it would give us something larger than or equal to 3.
So there are 900-1-3 numbers who are 3 digits long and whose sum of digits is greater than 2.
This answer simplifies to 896.
Answer: 23.25m
Step-by-step explanation:
C=2πr=2·π·3.7≈23.24779m
Answer:
<em>Well, Your answer will be is </em><em>D. 100 feet squared. </em><em>Because, </em>
<em>1. Multiply 10x6 and 10x4.
</em>
<em>
</em>
<em>2. Add 60 and 40, the results from the previous step.
</em>
<em>
</em>
<em>3. You get 100, or 100 feet squared. </em><em>Good Luck!</em>
<em>
</em>
<em />
