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zvonat [6]
3 years ago
12

A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test.

Each adult bike requires 6 hours to build and 4 hours to test. With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week. If c represents child bikes and a represents adult bikes, determine which system of inequality best explains whether the company can build 5 child bikes and 15 adult bikes in the week.
No, because the bike order does not meet the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100

No, because the bike order does not meet the restrictions of 4c + 4a ≤ 120 and 6c + 4a ≤ 100

Yes, because the bike order meets the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100

Yes, because the bike order meets the restrictions of 4c + 4a ≤ 120 and 6c + 4a ≤ 100
Mathematics
1 answer:
ivanzaharov [21]3 years ago
4 0

Answer:

Yes, because the bike order meets the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100

Step-by-step explanation:

4c + 6a ≤ 120:

You can set up the inequality 4c + 6a ≤ 120, because it takes 4 hours to build per child bike (c) and 6 hours to build an adult bike (a), all together this time cannot surpass 120 hours. That is why you use the 'less than or equal to' sign.

4c + 4a ≤ 100:

You can then set up the inequality 4c + 4a ≤ 100, because it takes 4 hours to test a child bike (c) and 4 hours to test an adult bike (a). Since 100 hours is the max amount of time they can use to test out bikes, you will use the 'less than or equal to' sign.

4(5) + 6(15) = 20 + 90 = 110. 110 is less than 120

4(5) + 4(15) = 20 + 60 = 80. 80 is less than 100

Yes, because the bike order meets the restrictions of 4c + 6a ≤ 120 and 4c + 4a ≤ 100

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