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Leokris [45]
3 years ago
5

Which type of factoring is used to factor the following expression: 2x^2 + 7x- 30

Mathematics
1 answer:
svetlana [45]3 years ago
7 0

Answer:

 (2x - 5) • (x + 6)

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A bag of numbered lottery balls contains the numbers 1 through 40. What is the probability that a randomly selected ball will be
RoseWind [281]

Answer:

37/40

Step-by-step explanation:

There are 3 numbers between 1 and 40 that are a multiple of 13: 13,26,39.

So, your probability should be 40-3/40, = 37/40.

3 0
3 years ago
Read 2 more answers
Let f(x)=2x+2 and g(x)=x^2<br> State the domain of the operation:<br> h(g(x))
faust18 [17]

Answer: the domain of f(x)=2x+2 is all real numbers and the domain of g(x)=x^2 is (0, infinity)

Step-by-step explanation:

there is no horizontal asymptote given

7 0
3 years ago
Ron has 25 coins with a total value of $ 4.30 . the coins are dimes and quarters. how many of each coin does he have?
Gwar [14]
25=d+q
4.30= .1d + .25q

25=d+q
-17.20=-.4d+-q

7.80= .6d
d=13...... 13 DIMES

25= 13+q
12=q....... 12 QUARTERS
4 0
3 years ago
in 2001, the population in a town was 12% more than it was in 2000. if the population was 25,160 in 2002, which is 10% more than
blagie [28]
2002=25,160
2001=22,644
2000=19,926.72 (need to round to 19,926)
2001:
25,160/10=2516
25,160-2516

2000:
22,644/10=2,264.4 (10%)
2,264.4/5=452.88 (2%)
2,264.4+452.88=2717.28 (12%)
22,644-2717.28=19.926.72
3 0
3 years ago
If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(
timama [110]

Use the change-of-basis identity,

\log_x(y) = \dfrac{\ln(y)}{\ln(x)}

to write

xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}

Use the product-to-sum identity,

\log_x(yz) = \log_x(y) + \log_x(z)

to write

xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}

Redistribute the factors on the left side as

xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}

and simplify to

xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)

Now expand the right side:

xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}

Simplify and rewrite using the logarithm properties mentioned earlier.

xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1

xyz = 2 + \dfrac{\ln(c)+\ln(a)}{\ln(b)} + \dfrac{\ln(a)+\ln(b)}{\ln(c)} + \dfrac{\ln(b)+\ln(c)}{\ln(a)}

xyz = 2 + \dfrac{\ln(ac)}{\ln(b)} + \dfrac{\ln(ab)}{\ln(c)} + \dfrac{\ln(bc)}{\ln(a)}

xyz = 2 + \log_b(ac) + \log_c(ab) + \log_a(bc)

\implies \boxed{xyz = x + y + z + 2}

(C)

6 0
2 years ago
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