Answer:
Step-by-step explanation:
I will show you by example. For the sin ratio, we have that the sin of the reference angle is equal to the side opposite the angle over the hypotenuse of the right triangle. We use this example for finding the ratio, knowing the angle:
found on your calculator. Because this is a special angle in a right triangle, we can also say, by looking at a 60 degree reference angle that the side across from the angle measures square root of 3, and the hypotenuse measures 2. So in terms of a radical,
If we don't know the angle, we use the 2nd button on our calculator to find it. For example, if our problem looked like this:
,
we are asked what angle has a sin ratio of 1/2. We find this angle by pressing the 2nd button on our calculator, then the sin button and you will see this on your screen:
Enter either a .5 or a 1/2 after that open parenthesis and hit enter and you'll get the angle measure. That's how you use the inverses to solve for missing angles.
the first picture you have to use B X L X H ( base, length and height) and i got 1728 mm^3
for the second one, you have to use the formula L X H ( P+ Q/2) ( length times height times the product of the base width plus the top width divided by 2 and i got the answer of 196 m^3.
i hope this helps :)
Answer:
the one that looks closest to this
Step-by-step explanation:
P-paratheses (do any math that has parentheses around the numbers) y=(2x5)+25
E-exponents (do the exponents next) y=(2x5)+5^2
M-multiplying. (Basically everything is self explanatory from here to then cuz im lazy to list examples)
Just basically if you don't use PEMDAS, you'll get the wrong answer
Answer:
Or if you want with the value of h too.
Step-by-step explanation:
Find the value of h and k by using the formula.
From y = x²-2
Substitute these values in the formula.
Therefore, h = 0.
Therefore, k = - 2.
From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.
These type of equation where b = 0 can also be both standard and vertex form.
