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3 years ago

Which is true about the volume or surface area of these prisms?

Mathematics

1 answer:

pshichka [43]3 years ago

5 0

Your answer is the second option: The surface area of B is greater than the surface area of A.

To find the surface area, I found the area of the three sides shown and added them together, and then multiplied the answer by 2, so:

B:
8 × 2 = 16
8 × 10 = 80
10 × 2 = 20
+
= 116
116 × 2 = 232 cm²

A:
5 × 8 = 40
5 × 4 = 20
8 × 4 = 32
+
= 92
92 × 2 = 184 cm²

So therefore B > A because 232 > 184

I hope this helps!

You might be interested in

Find the number of three digit number which are not divisible by 5

iragen [17]

Answer:

777 is an example of a three digit number that is not divisible by 5

Step-by-step explanation:

777/5 = 155.4

7 0

3 years ago

Read 2 more answers

Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

3 0

3 years ago

190 m<br> 90 m<br> 10 m<br> 40 m<br> What is the area

liberstina [14]

Answer:

Rect Area= Lw

3D Rect Area= 2(wh+lw+lh)

Step-by-step explanation:

7 0

3 years ago

Circle A is shown. Secant W Y intersects tangent Z Y at point Y outside of the circle. Secant W Y intersects circle A at point X

Gekata [30.6K]

By applying the theorem of intersecting secants, the measure of angle XYZ is equal to: A. 35°.

<h3>How to determine angle <XYZ?</h3>

By critically observing the geometric shapes shown in the image attached below, we can deduce that they obey the theorem of intersecting secants.

<h3>What is the theorem of intersecting secants?</h3>

The theorem of intersecting secants states that when two (2) lines intersect outside a circle, the measure of the angle formed by these lines is equal to one-half (½) of the difference of the two (2) arcs it intercepts.

By applying the theorem of intersecting secants, angle XYZ will be given by this formula:

<XYZ = ½ × (m<WZ - m<XZ)

Substituting the given parameters into the formula, we have;

<XYZ = ½ × (175 - 105)

<XYZ = ½ × 70

<XYZ = 35°.

By applying the theorem of intersecting secants, we can infer and logically deduce that the measure of angle XYZ is equal to 35°.

Read more on intersecting secants here: brainly.com/question/1626547

#SPJ1

6 0

1 year ago

If m ∠ A B F = ( 8 w − 6 ) ° m ∠ A B E = [ 2 ( w + 11 ) ] ° m ∠ E B F .

pashok25 [27]

The measure of angle EBF where he angle measures are given as m∠ABF = (8w − 6)° and m∠ABE = [2(w + 11)] is m∠EBF = 4w - 28

<h3>How to determine the measure of angle EBF?</h3>

The angle measures are given as

If m ∠ A B F = ( 8 w − 6 ) ° m ∠ A B E = [ 2 ( w + 11 ) ] ° m ∠ E B F

Rewrite the angle measures properly.

This is done, as follows

m∠ABF = (8w − 6)°

m∠ABE = [2(w + 11)]

The measure of angle m∠EBF is calculated as:

m∠ABF = m∠ABE + m∠EBF

Substitute the known values in the above equation

8w - 6 = 2(2w + 11) + m∠EBF

Open the brackets

8w - 6 = 4w + 22 + m∠EBF

Evaluate the like terms

m∠EBF = 4w - 28

Hence, the measure of angle EBF where he angle measures are given as m∠ABF = (8w − 6)° and m∠ABE = [2(w + 11)] is m∠EBF = 4w - 28