The area of Jill's soccer net is 3 times larger than area of Peter's soccer net.
<h3> Area of Peter's soccer net</h3>
The area of Peter's soccer net is determined by using area of rectangle as shown below;
A1 = 5.5 ft x 4 ft
A1 = 22 ft²
<h3> Area of Jill's soccer net</h3>
A2 = 5.5 ft x 12 ft
A2 = 66 ft²
<h3>Ratio of the area of their soccer net</h3>
A2/A1 = 66/22
A2/A1 = 3
Thus, the area of Jill's soccer net is 3 times larger than area of Peter's soccer net.
Learn more about area of rectangle here: brainly.com/question/25292087
Answer:
H, (3.5,-3), B, (3.5,5)
Step-by-step explanation:
Answer:
-12 / 17
Step-by-step explanation:
x | -1 | 2 | 5 | 8 |
-----------------------
y | 3 | -1 | -5 | -9 |
Piking the poits at the extreme:
x1 = - 1 ; y1 = 3
x2 = 8 ; y2 = - 9
Slope = Rise / Run
Rise = y2 - y1 = - 9 - 3 = - 12
Run = x2 - x1 = 8 - (-9) = 8 + 9 = 17
Hence,
Slope = - 12 / 17
Answer:
3/2 = X
Step-by-step explanation: