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galben [10]
3 years ago
9

The architect drew a design for the new kitchen. What is the area of the kitchen drawing?

Mathematics
1 answer:
nordsb [41]3 years ago
8 0

Answer:

24

Step-by-step explanation:

Area of the kitchen = Area small rectangle + area large rectangle + area triangle

Area small rectangle = (8-4)*1.5

Area large rectangle = (8-4)* 3

Area triangle = (1/2)*base*height = (1/2)*4*3

Area of the kitchen = (8-4)*1.5 +  (8-4)* 3 + (1/2)*4*3 = 24 cm²

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Nataly [62]

Answer: = 83 = 512 centimeters3

Step-by-step explanation:

5 0
3 years ago
If a circle has a diameter if (x+3) inches what is its circumference
Blizzard [7]

Answer:

π (x + 3) inch OR 3.14x + 9.42 inch

Step-by-step explanation:

Diameter (d) = x + 3

Circumference of a circle = πd

=》Circumference of a circle = π (x + 3) inch

If π = 3.14, then,

Circumference = 3.14 (x + 3)

Circumference = 3.14x + 9.42 inch

Hope it helps ⚜

6 0
2 years ago
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icang [17]

Answer:huh

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A regulation baseball field measures 90 feet between each base. What is the distance around the bases in yards
professor190 [17]
The distance between each base is 30 yards since 90*(1/3) = 90/3 = 30
In other words, 90 feet is equivalent to 30 yards (3 ft per 1 yard)

The total distance around the bases is 30*4 = 120 yards. This is the perimeter.
5 0
4 years ago
Please help i’m so stuck i can’t do calc for the life of me
KATRIN_1 [288]

Answer:

-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}  is the answer. See steps below.

Step-by-step explanation:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}\\\\-3x^5+11x^4+33x^3-26x^2-36x-6\\\\\mathrm{and\:the\:divisor\:}x^3+6x^2-3x-5:\\\\\mathrm{Quotient}=\frac{-3x^5}{x^3}=-3x^2\\\\\mathrm{Multiply\:}x^3+6x^2-3x-5\mathrm{\:by\:}-3x^2\:\:\rightarrow\:\:-3x^5-18x^4+9x^3+15x^2\\\\\mathrm{Subtract\:}-3x^5-18x^4+9x^3+15x^2\mathrm{\:from\:}-3x^5+11x^4+33x^3-26x^2-36x-6\mathrm{\:to\:get\:new\:remainder}.\\\\\mathrm{Remainder}=29x^4+24x^3-41x^2-36x-6

=-3x^2+\frac{29x^4+24x^3-41x^2-36x-6}{x^3+6x^2-3x-5}

Repeat the steps and you will reach a point where no further division is possible.

<u />

<u />=-3x^2+29x-150+\frac{946x^2-341x-756}{x^3+6x^2-3x-5}<u />

5 0
3 years ago
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