Answer:
-5x^2-2x
Step-by-step explanation:
When distributing, you multiply the term outside the brackets to all the terms in brackets.
If the term outside the bracket is negative, then when distributing/opening the brackets, the signs of the terms changes.
So in this prob. -x would multiply to both +5x and +2
-x*5x+-x*2
∴-5x^2-2x
The converse of t > r is r > t
<h3>What is a converse statement?</h3>
A converse statement is determined when both the hypothesis and conclusion are reversed or interchanged.
In this condition, the hypothesis is written as the conclusion and the conclusion is changed to be the hypothesis.
If a conditional statement is written as: x → y
The converse is then written as y → x
Where;
- x is the hypothesis
- y is the conclusion
Given the expression as;
t > r
We can see that;
- The variable 't' is the hypothesis
- The variable 'r' is the conclusion
The converse will be;
r > t
Hence, the converse is r > t
Learn more about converse statement here:
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Answer:
The best correct option is C
x = 1.79 to x = 3
Step-by-step explanation:
Making the sport off all little thing that crowed. They are still grouped into 7. Option C is theost appropriate.
<span>Use a straightedge to join points W and P and then points P and X. â–łWPX is equilateral.
Let's see now, Delmar has a line segment WX and has drawn 2 circles whose radius is the length of WX, centered upon W and centered upon X. Sounds to me that all he needs to do is select one of the intersections of those 2 circles and use that at the 3rd point of the equilateral triangle and draw a line from that point to W and another line from that point to X. Doesn't matter which of the two intersections he chooses, just needs to pick one. Looking at the available options, only the 1st one which is "Use a straightedge to join points W and P and then points P and X. â–łWPX is equilateral." matches my description, so that is the correct choice. The other choices tend to do rather bizarre things like create a perpendicular bisector of WX and for some unknown reason, claim that bisector is somehow a side of a desired equilateral triangle.</span>
I think you worded that a little wrong
