All categories

3 years ago

How many kilometers are there ??

Mathematics

1 answer:

irinina [24]3 years ago

5 0

Answer:

Step-by-step explanation:

1 hour=2 kg

10 hrs=10×2=20

Mark as brainliest please!

You might be interested in

Please! Find the values of x,y and Z

bearhunter [10]

Answer:

x = 24

y = 10

z = 17

Explanation:

It's long to explain, so heres a picture of how solved each. hope this helps!! :)

3 0

3 years ago

Find the ending balance $35,600 at 9% for 2 years

tino4ka555 [31]

Answer:

42,008

Step-by-step explanation:

6 0

3 years ago

The length of a rectangle is 1 ft less than double the width, and the area of the rectangle is 21 ft^2. Find the dimensions of t

ICE Princess25 [194]

Let the width be w, then length = 2w - 1

Area = length times width = w(2w - 1) = 21.

Thus, 2w^2 - w = 21 or 2w^2 - w - 21 = 0

Solving the quadratic equation gives that w = 3.5.

Therefore, width is 3.5 ft and length is 2(3.5) - 1 = 6 ft.

4 0

3 years ago

Which value of y below is the solution to the system shown below. A) y=6 B) y=-1 C) y=-4 D) y=8

Grace [21]

Answer:

Step-by-step explanation:

given the 2 equations

x + 2y = 27 → (1)

2x + 3y = 46 → (2)

Rearrange (1) expressing x in terms of y by subtracting 2y from both sides

x = 27 - 2y ← substitute into (2)

2(27 - 2y) + 3y = 46

54 - 4y + 3y = 46

54 - y = 46 ( subtract 54 from both sides )

- y = - 8 ( multiply both sides by - 1 )

y = 8 → D

4 0

3 years ago

An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the

DedPeter [7]

The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:

$d = -16t^2 + 1000$

Solution:

The object falls, its distance, d, above the ground after t seconds, is given by the formula:

$d = -16t^2 + 1000$

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

$-16t^2 + 1000 > 300$

Solve the inequality

Subtract 1000 from both sides

$-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700$

$16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < \frac{700}{16}\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{\frac{700}{16}}\\\\t < \pm 6.61$

Time cannot be negative

Therefore,

t < 6.61

And the inequality used is: $-16t^2 + 1000>300$

6 0

3 years ago