One A
y = e^x
dy/dx = e^x The f(x) = the differentiated function. Any value that e^x can have, the derivative has the same value. x is contained in all the reals.
One B
y = x*e^x
y' = e^x + xe^x Using the multiplication rule.
You want the slope and the value of the of y to be the same. The slope is y' of the tangent line
xe^x = e^x + xe^x
e^x = 0
This happens only when x is very "small" like x = - 4444444
y = e^x * ln(x) Using the multiplication rule again, we need the slope of the line with is y'
y1 = e^x
y1' = e^x
y2 = ln(x)
y2' = 1/x
y' = e^x*ln(x) + e^x/x So at x = 1 the slope of the line =
y' = e^1*ln(1) + e^1/1
y' = e*0+e = e
y = mx + b
y = ex + b
to find b we use y= e^x ln(x)
e^x ln(x) = e*x + b
e^1 ln(1) = e*1 + b
ln(1) = 0
0 = e + b
b = - e
line equation and answer.
y = e*x - e
Answer:
I believe it is y equals 3 minus 2x.
I believe that when finding the radius of a circle you half the diameter, but when finding the circumference of a circle you need to multiply the diameter (14cm) by pi.
So 14xpi= 43.98229715
But it can be simplified/ rounded to 44cm.
Of course I might be incorrect so do please correct me if I am wrong.
Answer:
x = 9.9 in.
Step-by-step explanation:
area of triangle = base * height /2
49 = x*x /2
49*2 = x^2
98 = x^2
= x
= x
9.9 = x
Answer:
y+2= -1/5(x+1)
Step-by-step explanation:
if lines are perpendicular their slopes are negative reciprocal
y=mx+b where m is the slope
y=5x-10 has the slope 5 so a perpendicular line will have slope -1/5
equation point slope form
(y-y1) = m(x-x1) where m is slope, and (x1,y1) any point that belongs to the line
y+2= -1/5(x+1)
