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2 years ago

What type of budget involves placing money into envelops?

Mathematics

2 answers:

svetoff [14.1K]2 years ago

5 0

Answer:

B. Physical budget

Step-by-step explanation:

physical budget is when the user is separating their payments into individual envelopes to help avoid over spending and managing money.

Mama L [17]2 years ago

4 0

Physical Budgeting is what you're looking for!

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What is the equation of the line that passes through the point (-2,7) and has a slope of zero

Lina20 [59]

Answer:

Equation of the line that passes through the point (-2,7) and has a slope of zero is given as

$y=7$

Step-by-step explanation:

Equation of line is given as

$y-y_1=m(x-x_1)$ -----------(1)

Here

$m=0 \ \ \ and \ \ \ (x_1, y_1) = (-2, 7)$

Substituting values in equation (1)

$y-7=0(x+2)\\y=7$

5 0

2 years ago

The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i

kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

$S=\pi r\sqrt{r^2+h^2}$

and volume,

$V=\frac{1}{3}\pi r^2 h$

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

$f(r,h)=\frac{1}{3}\pi r^2 h$

subject to,

$g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)$

We know for maximum volume $r\neq 0$ . So let $\lambda$ be the Lagranges multipliers be such that,

$f_r=\lambda g_r$

$\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)$

And,

$f_h=\lambda g_h$

$\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}$

$\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)$

Substitute (3) in (2) we get,

$\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)$

$\implies h^2=2r^2$

Substitute this value in (1) we get,

$\pi r\sqrt{h^2+r^2}=8$

$\implies \pi r \sqrt{2r^2+r^2}=8$

$\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252$

Then,

$h=\sqrt{2}(1.21252)\equiv 1.71476$

Hence largest volume,

$V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114$

3 0

2 years ago

3 Parts with a picture. Thanks!

tatuchka [14]

We have $8.50 an hour gross minus $2.15 an hour tax and bennys. Then $3.75 daily expense. In one week our net take-away y after x hours is

y = x(8.50 - 2.15) - 5(3.75)

That's the answer, or we can simplify it to

Answer: y = 6.35 x - 18.75

Answer: The slope, 6.35, is the net dollars per hour <em>before weekly expenses.</em>

Answer: The y intercept, -18.75, is the weekly expense, negative because it's an expense.

To make $120 in a week, we solve for x where y=120

120 = 6.35x - 18.75

138.75 = 6.35 x

x = 138.75 / 6.35 = 21.8503937007874

That wasn't the nice round number I was expecting/hoping for. I don't see a mistake so let's go with

Answer: 21.85 hours to make $120

7 0

2 years ago

(6.253•10^-2)(7.112x10^3) in scientific notation

zlopas [31]

Answer:

4.4471336 * 10^2.

Step-by-step explanation:

(6.253•10^-2)(7.112x10^3)

= 6.253*7.112 * 10^-2*10^3

= 44.471336 * 10^1

= 4.4471336 * 10^2.

7 0

2 years ago

A car wash detailed 256 cars in 8 hours. At what rate did the car wash detail

Minchanka [31]

32 cars per hour. If you do 256 divided by 8 you get 32.

Hope this helped!

4 0

2 years ago