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Veronika [31]
3 years ago
9

What type of budget involves placing money into envelops?

Mathematics
2 answers:
svetoff [14.1K]3 years ago
5 0

Answer:

B. Physical budget

Step-by-step explanation:

physical budget is when the user is separating their payments into individual envelopes to help avoid over spending and managing money.

Mama L [17]3 years ago
4 0
Physical Budgeting is what you're looking for!
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What is the expanded form of 43x65
bazaltina [42]
43×65=2,795 expand form = 2,000+700+90+5=7,795
8 0
3 years ago
Calculate the radius of a circle if it’s circumference is 37.7cm
Eddi Din [679]
Circumference = 2\pir

Solve for r.

2\pir = 37.7
Divide both sides by 2.

\pir = 18.85
Divide both sides by \pi.

r = 6

The radius is 6 cm.
4 0
3 years ago
Multiply. 9x/4b•2bx/3x^5. Simplify your answer as much as possible
stich3 [128]

Answer:

3/2x^3

Step-by-step explanation:

multiply the numerators and the denominators

6 0
4 years ago
Find a formula for Y(t) with Y(0)=1 and draw its graph. What is Y\infty?
tino4ka555 [31]

Answer:

(a)\ y(t)\ =\ -2e^{-2t}+3

(b)\ y(t)\ =\ 4e^{-2t}-3

Step-by-step explanation:

(a) Given differential equation is

   Y'+2Y=6

=>(D+2)y = 6

To find the complementary function, we will write

D+2=0

=> D = -2

So, the complementary function can be given by

y_c(t)\ =\ C.e^{-2t}

To find the particular integral, we will write

y_p(t)\ =\ \dfrac{6}{D+2}

          =\ \dfrac{6.e^{0.t}}{D+2}

           =\ \dfrac{6}{0+2}

           = 3

so, the total solution can be given by

y_(t)\ =\ C.F+P.I

         =\ C.e^{-2t}\ +\ 3

y_(0)=C.e^{-2.0}\ +\ 3

but according to question

1 = C +3

=> C = -2

So, the complete solution can be given by

y_(t)\ =\ -2.e^{-2.t}\ +\ 3

(b) Given differential equation is

   Y'+2Y=-6

=>(D+2)y = -6

To find the complementary function, we will write

D+2=0

=> D = -2

So, the complementary function can be given by

y_c(t)\ =\ C.e^{-2t}

To find the particular integral, we will write

y_p(t)\ =\ \dfrac{-6}{D+2}

           =\ \dfrac{-6.e^{0.t}}{D+2}

           =\ \dfrac{-6}{0+2}

           = -3

so, the total solution can be given by

y_(t)\ =\ C.F+P.I

         =\ C.e^{-2t}\ -\ 3

y_(0)\ =C.e^{-2.0}\ -\ 3

but according to question

1 = C -3

=> C = 4

So, the complete solution can be given by

y_(t)\ =\ 4.e^{-2.t}\ -3

4 0
3 years ago
Could you help me with this question?
Dafna11 [192]

Answer:

2nd

Step-by-step explanation:

5=a^x

5/a

a^x/a

take a to the top

a^x.a^-¹

a^x-1

hope u understand

7 0
3 years ago
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