Answer:
One plane has a speed of 450 km/h and the other has a speed of 900 km/h.
Step-by-step explanation:
I am going to say that:
The speed of the first plane is x.
The speed of the second plane is y.
One plane is flying at twice the speed of the other.
I will say that y = 2x. We could also say that x = 2y.
Two airplanes leave an airport at the same time, flying in the same direction
They fly in the same direction, so their relative speed(difference) at the end of each hour is y - x = 2x - x = x.
If after 4 hours they are 1800 km apart, find the speed of each plane
After 1 hour, they will be x km apart. After 4, 1800. So
1 hour - x km apart
4 hours - 1800 km apart
4x = 1800
x = 1800/4
x = 450
2x = 2*450 = 900
One plane has a speed of 450 km/h and the other has a speed of 900 km/h.
Answer:it’s a
Step-by-step explanation:
Answer: " m = zC / (C − z) " .
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Explanation:
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Given: 1/C + 1/m = 1/z ; Solve for "m".
Subtract "1/C" from each side of the equation:
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1/C + 1/m − 1/C = 1/z − 1/C ;
to get: 1/m = 1/z − 1/C ;
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Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
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mzC {1/m = 1/z − 1/C} ;
to get: zC = mC − mz ;
Factor out an "m" on the "right-hand side" of the equation:
zC = m(C − z) ; Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;
zC / (C − z) = m(C − z) / m ; to get: 24/8 = 3 24
zC/ (C − z) = m ; ↔ m = zC/ (C − z) .
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The answer in order is b a c
