Ken's distance is: d(t)=1.7t
Ken's shadow is:
(14-6)/d(t)=14/s
8/d(t)=14/s
s=14d(t)/8
s=1.75d(t) and using the value for d(t) we have:
s=1.75(1.7t)
s=2.975t and if you want it in terms of d, d=1.7t, t=d/1.7 so
s=2.975(d/1.7)
s=1.75d
Answer:
probability for 3 on a dice (P3) in one dice =

probability for even no. of a dice (Pe) =

Therefore, the probability of finding 3 on one dice and even on another (P) = P3 + Pe

Answer:
A)
Step-by-step explanation:
Answer: what is the answer
Step-by-step explanation:
That's easy 327 <span>÷ 36 is 9.083</span>