Write an algebraic expression for the phrase. the sum of f and 6
1 answer:
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Your question is incomplete, here is the complete form.
Points J, K and L are collinear with J between L and K. If KJ = 2x - 3, LK = 9x + 7 and LJ = 4x - 8, solve for x:
Answer:
The value of x is -6 ⇒ B
Step-by-step explanation:
∵ J, K, and L are collinear
→ That means they form a straight segment
∵ J is between K and L
→ That means J divides LK into two segments KJ and LJ
∴ LK = KJ + LJ
∵ LK = 9x + 7
∵ KJ = 2x - 3
∵ LJ = 4x - 8
→ Substitute them in the equation above
∴ 9x + 7 = (2x - 3) + (4x - 8)
→ Add the like terms in the right side
∵ 9x + 7 = (2x + 4x) + (-3 - 8)
∴ 9x + 7 = 6x + -11
∴ 9x + 7 = 6x - 11
→ Subtract 7 from both sides
∵ 9x + 7 - 7 = 6x - 11 - 7
∴ 9x = 6x - 18
→ Subtract 6x from both sides
∵ 9x - 6x = 6x - 6x - 18
∴ 3x = -18
→ Divide both sides by 3
∵
∴ x = -6
∴ The value of x is -6
Answer:
Ratio of area of triangles MNP and ABC is 1.05
Step-by-step explanation:
There are 2 triangles ABC and MNP.
We are given that ,m∠A = m∠M.
AB = 16 and AC = 10.
MN = 7 and MP = 24.
Area of a triangle ∝ Product of any two sides.
So area of triangle ABC ∝ 16
Area of triangle ABC = 160 ,
where k is a constant.
So area of triangle MNP ∝ 7
Area of triangle MNP = 168
So ratio of area of triangles =
=
= 1.05
9514 1404 393
Answer:
x^(1/6)
Step-by-step explanation:
The applicable rule of exponents is ...
(a^b)/(a^c) = a^(b-c)
__
Here, we have a=X, b=1/2, c=1/3, so the quotient is ...
(X^(1/2))/(X^(1/3)) = X^(1/2 -1/3) = X^(1/6)
_____
Expressed as a radical, this is ...
Answer:
(See explanation below for further details)
Step-by-step explanation:
Any point in rectangular form can be described in terms of radius and angle of the circle. That is:
Since circunference is divided into 8 equal parts, the point can be modelled as:
The approximate radian and degree values for one circle are:
Radians
Degrees