A) The solutions to this set of equation is where the graphs cross. They cross at point (-3, -2).
B) The solutions for f(x) would be points that fall on the graph of f(x). Two possible points are (-3, -2) and (-7, 3)
C) These 2 functions cross at (4, 1). That is the solution.
A square with sides of 4 for perimeter and area of a rectangle with length 2 width 6<span />
Answer:
The area is 5 units²
Step-by-step explanation:
∵ The area of the square of side length 3 which contains
the quadrilateral ABCD = 3 × 3 = 9 units²
∵ The area of the 4 triangles on the sides of the quadrilateral ABCD
= 1/2(2)(1) + 1/2(1)(2) + 1/2(2)(1) + 1/2(1)(2) = 4 units²
∴ The area of quadrilateral ABCD = 9 - 4 = 5 units²
Answer:
21 or 28
Step-by-step explanation:
Area = LxW
7x3 = 21
7x4 = 28
