5x^8-20x^4 5x^8 + 20x^6 + 20^4 Which real values of x make the expression undefined?

For any integer x,x2-x will always produce an even value

Levart [38]

Consider expression $x^2-x.$ First, you can factor it:

$x^2-x=x(x-1).$

Since x is integer number, then you can see that x-1 is previous integer number (x-1 is 1 unit smaller than x).

Therefore, x-1 and x are two consecutive integers. When you have two consecutive integers, one of them is always even and one is always odd. Multiplying even integer number by odd integer number you always get even integer number.

Thus, $x^2-x$ is always even.

8 0

3 years ago

57

Lapatulllka [165]

Could you show a picture so i could understand a little bit better?

6 0

3 years ago

Please help me with this sum

mihalych1998 [28]

The answer is 1
6 -
6

8 0

4 years ago

Which equation is correct

Anika [276]

For this case we have to define trigonometric relations of rectangular triangles that:

The cosine of an angle is given by the leg adjacent to the angle on the hypotenuse of the triangle.

The sine of an angle is given by the leg opposite the angle on the hypotenuse of the triangle.

Then, according to the figure we have:

$Sin (G) = \frac {15} {17}\\Cos (G) = \frac {8} {17}$

Answer:

$Sin (G) = \frac {15} {17}$

Option D

5 0

3 years ago

The floor of a drawing room consists of 2000 tiles. Each of the tiles is rectangular in

wlad13 [49]

Step-by-step explanation:

<h2>☼︎Given :</h2>

The floor of a drawing room consist of 2000 tiles .Each tiles is rectangular in shape , of dimensions ,30 cm × 20 cm.

$\rule{200pt}{3pt}$

Area of the room.

$\rule{200pt}{3pt}$

<h2>☼︎Solution :</h2>

~ Formula Used:

$\large{\blue{\bigstar}} \: \: {\underline{\boxed{\pink{\sf{ Area{\small_{(Rectangle)}} = Length \times Breadth }}}}} \: \: {\blue{\bigstar}}$

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

~ Calculating the Area of Tiles 

${➙ \: {\sf{ Area = Length \times Breadth}}}$

${➙ \: {\sf{ Area = 30 \times 20 }}}$

${\sf{➙ \: Area \: of \: 1 Tiles = {\purple{\bf{ 600 \: cm² }}}}}$

$\qquad{━━━━━━━━━━━━━━━━━━━━━}$

~ Calculating Area of the Drawing Room :

${➙ \: {\sf{ Area \: of \: Room \: = No. \: of \: Tiles \times Area \: of \: 1 \: Tile }}}$

${➙ \: {\sf{ Area \: of \: Room \: = 2000 \times 600 }}}$

${\qquad{\sf{ Area \: of \: Room \: = {\color{darkblue}{\bf{ 1200000 \: cm² }}}}}}$

$\qquad{━━━━━━━━━━━━━━━━━━━━━}$

~ Therefore :

❝ Area of the Drawing room is 1200000 cm² or 12000 m² . ❞

$\begin{gathered} \\ {\blue{\underline{\red{\rule{300pt}{9pt}}}}}\end{gathered}$

8 0

3 years ago

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