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ladessa [460]
3 years ago
10

The dimensions of a small juice box are 11 cm by 4 cm by 7 cm. The super-size juice box has the same height of 11 cm but double

the volume. Give two sets of the possible dimensions of the super-size juice box and the volume.
Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
4 0

Answer:

Two sets of the dimensions may be 4cm×14cm×11cm or 7cm×8cm×11cm and the volume will be 616 cm³.

Step-by-step explanation:

Dimensions of a small juice box are 11cm×4cm×7cm.

Volume of the small juice box = 11×4×7 = 308 cm³

Height of the super size juice box is same as small juice box but volume is double.

Let length and width of the super size juice box are x and y cm.

So volume = 11xy cm³ = 2(Volume of small juice box)

11xy = 2×308

xy = \frac{2\times 308}{11}

xy = 56

Therefore, two sets of the dimensions may be 4cm×14cm×11cm or 7cm×8cm×11cm and the volume will be 616 cm³.

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vodomira [7]

Answer:

0.2498

Step-by-step explanation:

Number of 4 digit numbers that can be formed from the digit (0 - 8), assume number can't start from 0

Thus ;

First digit = (1, 2, 3, 4, 5, 6, 7, 8) = 8 ways

Next three digits = (0, 1, 2, 3, 4, 5, 6, 7, 8) = 9 ways

Hence,

Total possible outcomes = sample space = (8 * 9 * 9 * 9) = (8 * 9^3 ) = 8 * 729 = 5832

Required = number greater Than 7000

For number to be greater Than 7000, starting digit should be either 7 or 8

Hence,

First digit = 2 ways

Next three digits = 9 ways

Also excluding 7000

Hence, Number of digits above 7000;

2 * 9^3 = 2 * 729 = 1458 - 1 = 1457

Hence,

Probability = 1457 / 5832

= 0.2498285

= 0.2498

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sergiy2304 [10]

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A rope of length 18 feet is arranged in the shape of a sector of a circle with central angle O radians, as shown in the
creativ13 [48]

Answer:

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Let

r ---> the radius of the sector

s ---> the arc length of sector

Find the radius r

we know that

2r+s=18

s=r \theta

2r+r \theta=18

solve for r

r=\frac{18}{2+\theta}

step 2

Find the value of s

s=r \theta

substitute the value of r

s=\frac{18}{2+\theta}\theta

step 3

we know that

The area of complete circle is equal to

A=\pi r^{2}

The complete circle subtends a central angle of 2π radians

so

using proportion find the area of the sector by a central angle of angle theta

Let

A ---> the area of sector with central angle theta

\frac{\pi r^{2} }{2\pi}=\frac{A}{\theta} \\\\A=\frac{r^2\theta}{2}

substitute the value of r

A=\frac{(\frac{18}{2+\theta})^2\theta}{2}

A=\frac{162 \theta}{(\theta+2)^2}

Convert to function notation

A(\theta)=\frac{162 \theta}{(\theta+2)^2}

6 0
4 years ago
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