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3 years ago

Please help me with this question!!

Mathematics

1 answer:

mario62 [17]3 years ago

3 0

Answer:

Step-by-step explanation:

Cosine is positive in quadrants I and IV.

Cosecant (also sine) is negative in quadrants III and IV.

The quadrant where cos > 0 and csc < 0 is quadrant IV.

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A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimat

Vedmedyk [2.9K]

Using the z-distribution, we have that:

a) A sample of 601 is needed.

b) A sample of 93 is needed.

c) A. Yes, using the additional survey information from part (b) dramatically reduces the sample size.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

For this problem, we consider that we want it to be within 4%.

Item a:

The sample size is <u>n for which M = 0.04.</u>

There is no estimate, hence $\pi = 0.5$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5(0.5)}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.5(0.5)}$

$\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.04}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.04}\right)^2$

$n = 600.25$

Rounding up:

A sample of 601 is needed.

Item b:

The estimate is $\pi = 0.96$ , hence:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.96(0.04)}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.96(0.04)}$

$\sqrt{n} = \frac{1.96\sqrt{0.96(0.04)}}{0.04}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.96(0.04)}}{0.04}\right)^2$

$n = 92.2$

Rounding up:

A sample of 93 is needed.

Item c:

The closer the estimate is to $\pi = 0.5$ , the larger the sample size needed, hence, the correct option is A.

For more on the z-distribution, you can check brainly.com/question/25404151

8 0

2 years ago

A cat is to receive 90 kcal of a canned food at each meal. The food has a caloric

Mnenie [13.5K]

Answer:

The cat should receive 1/5 of the can of food at each meal.

Step-by-step explanation:

Given that a cat is to receive 90 kcal of a canned food at each meal, and the food has a caloric density of 450 kcal per can, to determine what fraction of a can it should receive at each meal, the following calculation must be performed:

1 / (450/90) = X

1/5 = X

Thus, the cat should receive 1/5 of the can of food at each meal.

5 0

3 years ago

What fraction is greater than 2/3

lutik1710 [3]

2/3 is basically 0.6666666667 which is the same as 66% so any percentage bigger than 66% such as 75% (0.75) which is 3/4 (as a fraction) is bigger than 2/3

8 0

3 years ago

The drawing plan for an art studio shows a rectangle that is 19.2 inches by 8 inches. The scale in the plan is 4 in.: 5 ft. Find

Svetradugi [14.3K]

Length: 19 feet
Width: 10 feet
Area: 190 feet

4 0

3 years ago

1.which side of AFED does AB in AABC correspond to?

erma4kov [3.2K]

Rotate one of them so the right angle is in the same orientation as the other one.

1. AB = DE

2. CB = FE

3. AC = DF

4. Compare the length of two known sides: cb and EF

CB = 3 and EF = 8

8/3 = 2 2/3 scale factor

5. Ab is side de. Multiply the length of ab by the scale factor:

4 x 2 2/3 = 10 2/3

6. FD = sqrt ( 10 2/3^2 + 8^2)

FD = 13 1/3

6 0

3 years ago