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Luda [366]
3 years ago
10

Please help me with this question!!

Mathematics
1 answer:
mario62 [17]3 years ago
3 0

Answer:

  IV

Step-by-step explanation:

Cosine is positive in quadrants I and IV.

Cosecant (also sine) is negative in quadrants III and IV.

The quadrant where cos > 0 and csc < 0 is quadrant IV.

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Step-by-step explanation:

To make it easy let's start by organizing our information :

  • AC=12 AND BD=8
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  • K and L are the midpoints of sides AD and CD
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What do you think of when you hear a right triangle ?

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AC and BD  are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

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  • BC²= 52⇒\sqrt{52}=BC

Now we khow that : AB=BC=CD=AD=\sqrt{52}

This isn't enough . Let's try to figure out a way to calculate the length of KL  wich is the base of the triangle

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I smell something . yes! Thales theorem

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Now we have the length of the base kl

Now the big boss the height :

  • notice that you khow the length of KL
  • BD crosses kl from its midpoint and DL = \sqrt{52} /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

  • DL²=(KL/2)²+D²
  • 52/4= 9+ D²
  • D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

  • A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

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