Answer:
510 gorillas
Step-by-step explanation:
In this problem, the population of gorillas is decreasing at a rate of 3.5 % per year.
We can write an expression for the population of gorillas as follows:
where
n(t) is the number of gorillas after t years
is the number of gorillas at t = 0
r is the grow rate of the population
t is the number of years
Here we have:
is the number of gorillas when t = 20 years
is the grow rate of the population
So the equation becomes:
And solving for , we find the initial number of gorillas:
Answer:
This is a function y = mx + b:
- You start with $50, so the y-intercept(b) is 50.
- Adding $20 a week means that the slope(m) is 20.
So, the function would be y = 20x + 50, where y is the dollar amount after x weeks and x cannot be greater than 12.
Answer:
10
Step-by-step explanation:
4x-12=28
4x = 40
x = 10 (Answer)
D=110
t=50
r=x
solution
110=50x
x=110/50
x=1hr. 20mins
or
x=1 X 20/60
x=1 1/3 hr
The answer is 2.25x10^-17
Are you in k12 too?