Find the area of this rectangle 7 in 10 in

zlopas [31]

6√2 + 4 √32
try to get the same number "2" remaining under the root sign by finding what # times 2 gives 32
6√2 + 4√2×√16
since 16 is a perfect Square √16 gives 4
therefore.
6√2 + 4 ×4 √2
6√2 +16√2
these are Like terms so add them
which would give u
22√2
hoped i helped, feel free to ask any question XOX

3 0

3 years ago

Use The Alternate Interior Angles Theorem diagram to answer the question. Give the missing reason in this proof for the letter g

Serjik [45]

The missing reasons in the proof using the Alternate Interior Angles Theorem diagram that is given are:

a. Corresponding angles

b. Vertical Angles, and

c. Alternate interior angles

Two angles lying opposite each other along a transversal, and are within the two lines crossed by the transversal are referred to as alternate interior angles.

According to the Alternate Interior Angles Theorem, the two alternate interior angles are congruent to each other.

Let's state out our proof using the image given:

Statement 1: line l is parallel to line m

Reason: Given

Statement 2: $\angle 2 \cong \angle 6$

Reason: Corresponding Angles (both angles occupy the same corner, hence they correspond to each other. Corresponding angles have the same measure).

Statement 3: $\angle 4 \cong \angle 2$

Reason: Vertical angles (both angles are directly opposite each other as they share the same point, which makes them vertical angles. Vertical angles have equal measure).

Statement 4: $\angle 6\cong \angle 4$

Reason: Alternate Interior Angles (applying the transitive property which says if a = b, and b = c, then a = c, therefore, since $\angle 2 \cong \angle 6, $ and $ \angle 4 \cong \angle 2, $ then $ \angle 6 \cong \angle 4$ )

In conclusion, the missing reasons in the proof using the Alternate Interior Angles Theorem diagram that is given are:

a. Corresponding angles

b. Vertical Angles, and

c. Alternate interior angles

Learn more here:

brainly.com/question/18898800

4 0

2 years ago

If we accept the null hypothesis when, in fact, it is false, we have: committed a Type II error. a probability of being correct

Greeley [361]

Answer:

Correct option: Type II error.

Step-by-step explanation:

In statistical hypothesis testing two kind of errors can be committed by the researcher.

Type I error: The probability of rejecting a null hypothesis when in fact it is true.
Type II error: The probability of not rejecting a null hypothesis when in fact it is false.

The power of the test is defined as the probability of rejecting a false null hypothesis. It is denoted by β.

Then the probability of Type II error can be defined as:

P (Type II error) = 1 - β.

The power of the test is affected by the significance level.

If the significance level is less than the power is also less.

The significance level is related to the p-value of the test.

So the P(Correct) = 1 - p-value.

7 0

3 years ago

For the graph x = 1 find the slope of a line that is perpendicular to it and the slope of a line parallel to it. Explain your an

Hitman42 [59]

First, x=1 is a vertical line. A line that is perpendicular would be horizontal so it would have a slope of 0. A line parallel to it would be vertical too so it would have and infinite gradient.

3 0

4 years ago

The coordinate of point B is -6 and the coordinate of point E is 2.

natita [175]

Answer:

4

Step-by-step explanation:

just because i just took it

6 0

3 years ago

Find the area of this rectangle7 in10 in​

Find the area of this rectangle7 in10 in