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nataly862011 [7]
3 years ago
5

Which of the following groups of parrots is most likely in Hardy-Weinberg equilibrium?

Biology
1 answer:
Stolb23 [73]3 years ago
3 0

Answer:

B. A group with 30 DD parrots, 40 Dd parrots, and 30 dd parrots.

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The three phases of signal transduction is (1) reception, (2) transduction, and (3) response. Reception involves the binding of a ligand, may it be a hormone or a neurotransmitter; to a receptor, may it be a membrane receptor, cytosolic receptor, or a nuclear receptor. After binding of the ligand to the receptor, there will be signal transduction of events that will ultimately form a response. For instance, insulin actin on the insulin receptor will trigger a series of events that will increase the transcription of the gene translating for glucose transporters and ultimately, increase the number of glucose transporters embedded in the cell membrane leading to increased glucose uptake in tissues.
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What is the representative organism for a sponge?
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Phylum Porifera

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What molecule is represented by the molecular model shown below?
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Population A is made up of living animals. The members of population B feed on these living animals. What type of relationship i
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Predator prey

Explanation:

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The second image illustrates a predator-prey cycle where an increase in the prey numbers will lead to an increase in the predator numbers. This in turn will lead to a decrease in the prey number which in turn will also lead to a decrease in the predator's numbers.

The third image is a trophic or ecological pyramid in which X are the primary producers (ex. plants), Y are the animals that feed on these (prey) and Z are the predators that feed on Y. In general, top predators are not hunted and eaten by other species which is why they are at the top of the pyramid.

7 0
2 years ago
A gas storage tank at a large industrial plant is designed to provide fuel under constant pressure. When the plant is shut down
Alex

Answer: Temperature on monday morning is 319,5K

Explanation: This is an example of Gay Lussac law on gases which states that at constant volume, pressure and temperature are directly related, so if one raises the other one does as well.

The equation that follow the law is :

P1 / T1 = P2/T2 where 1 is the initial pressure and temperature and 2 is the final state.

In this equation, values have to be expressed in atm  for pressure and Kelvin for temperature.

P1 = 115 kPa .\frac{1 atm}{101,3kPa} = 1,135 atm

P2 = 108,75 kPa .  \frac{1atm}{101,3kPa} =  1,073 atm

The missing value is T2 (monday temperature), so we have to clear it from the equation

T2 =P2.T1/P1

Replacing values:

T2 = 1,073 atm . 338K /1,135 atm

T2 = 319,5 K

7 0
3 years ago
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