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Soloha48 [4]
3 years ago
14

5/7 divided by 1/7?? Plez help

Mathematics
2 answers:
Jet001 [13]3 years ago
6 0
The answer will be 14/5
MAVERICK [17]3 years ago
4 0

Answer:5

Step-by-step explanation:When we divide two fractions, such as 5/7 ÷ 1/7, we flip the second fraction and then we simply multiply the numerators with each other and the denominator with each other.

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A fruit juice company includes 1.247 ounces of orange juice in a 6.85 ounce bottle of mixed fruit juice. How much of the bottle
Svet_ta [14]

Answer:

5.603 ounces

Step-by-step explanation:

From the information given, you know the ounces of orange juice included in a bottle and the ounces of mixed fruit juice that the bottle has. So, to be able to determine how much of the bottle of mixed fruit juice is not orange juice​, you have to subtract the ounces of orange juice in the bottle from the ounces of mixed fruit juice that it has:

6.85-1.247=5.603

According to this, the answer is that the bottle of mixed fruit juice has 5.603 ounces that are not of orange juice.

7 0
3 years ago
Y is two times the value of x<br><br> The equation is y=
MissTica

Y=2x should be correct

7 0
3 years ago
How to find slope of tangent line at a given point?
tino4ka555 [31]
Are there options for this question? Maybe use the point slope formula 
3 0
3 years ago
Graph the following transformation
castortr0y [4]
Dkckdkckkdkckdkckdkckdkfkrkkfneedstobeatleast30characterslongvkfkckdkckkdck

6 0
3 years ago
I don’t know how to do this
stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as x approaches the edges. For example,

g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}

has two pieces, 2x+5 and x^2-10, both of which are continuous by themselves on the provided intervals. In order for g to be continuous everywhere, we need to have

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)

By definition of g, we have g(-3)=2(-3)+5=-1, and the limits are

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1

\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1

The limits match, so g is continuous.

For the others: Each of the individual pieces of f,h are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.

4 0
3 years ago
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