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3 years ago

9

Lourdes is listening to an audio book that is 9 hours long. She has listened for 6 1/6 hours so far. How many hours of listening

time are left.

1 answer:

aivan3 [116]3 years ago

4 0

9 - 6 1/6 =
= 2 5/6 hours = 2 hours 50 minutes
Answer:
2 5/6 hours of listening time are left.
Thank you.

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A Rectangular has area 12a^2 and perimeter 14a what are the dimensions of this Rectangular?

Nataliya [291]

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Answer:

3a by 4a

Step-by-step explanation:

For dimensions L and W, the area and perimeter are ...

A = LW = 12a^2

P = 2(L+W) = 14a

Using the second equation, we can find L:

L +W = 7a . . . . . divide by 2

L = 7a -W

Substituting into the area formula gives the quadratic ...

(7a -W)(W) = 12a^2

W^2 -7aW +12a^2 = 0 . . . . arrange in standard form

(W -3a)(W -4a) = 0 . . . . . . . factor (find factors of 12 that total 7)

Then we have the two solutions ...

W = 3a, L = 4a

W = 4a, L = 3a

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3 years ago

3 3/5+ 4 1/8=<br> PLS PLS PLS PLS ANSWER

Jet001 [13]

I think the answer is 7.725 so sorry if I’m wrong but see if that answer is correct

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2 years ago

Giving 20 points to the right person if your wrong your getting reported

Paha777 [63]

Answer:

730

Step-by-step explanation:

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3 years ago

The distribution of IQ scores can be modeled by a normal distribution with mean 100 and standard deviation 15.

evablogger [386]

Answer:

4.4% of the population with IQ between 120 and 125.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100

Standard Deviation, σ = 15

We are given that the distribution of IQ scores is a bell shaped distribution that is a normal distribution.

a) Let X be a person's IQ score.

Then, density functions for IQ scores is given by:

$P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{z^2}{2}}\\\\\text{where,}\\\\z = \frac{x-\mu}{\sigma}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-\mu)^2}{2\sigma^2}}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-100)^2}{450}}$

b) P(population with IQ between 120 and 125.)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

$P(120 \leq x \leq 125) = P(\displaystyle\frac{120 - 100}{15} \leq z \leq \displaystyle\frac{125-100}{15}) = P(1.33 \leq z \leq 1.66)\\\\= P(z \leq 1.66) - P(z < 1.33)\\= 0.952 - 0.908 = 0.044 = 4.4\%$

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3 years ago

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Answer:

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Step-by-step explanation:

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