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kiruha [24]
3 years ago
14

What's the least common multiple of 9 and 15

Mathematics
1 answer:
Alona [7]3 years ago
6 0
3 is the answer to your question
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Two blocks are connected by a very light string passing over a massless and frictionless pulley. The 20.0 N block moves 75.0cm t
Angelina_Jolie [31]
The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus, 
1.22 a = 12.0 - T  (eqn 1)
and for the 20.0 N block: 
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction) 
2.04 a = T - 6.5  (eqn 2) 

[eqn 1] + [eqn 2] → 3.26 a = 5.5 
a = 1.69 m/s² 


Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5 
T = 9.95 N 

Now want the resultant force acting on the 20.0 N block: 
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N 
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>

75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m 
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
3 0
2 years ago
Can you please help me I plead you
Levart [38]

Answer:

Question 2

x is approximately 15.038 or 15 days

Question 3

$3.41

Question 4

31.1

Step-by-step explanation:

Question 2

5.2 km/1 day =78.2 km/x days

Multiply both sides by x

5.2x=78.2

divide by 5.2

x is approximately 15.038

or 15 days

Question 3

350-(262.94+83.65)

$3.41

Question 4

22(1.3)+2.5

31.1 m

5 0
2 years ago
A triangle has two angles that measure 18.6 degrees and 113.4 degrees respectively. what is the measure of the third angle?
spin [16.1K]

Answer:

x = 48

Step-by-step explanation:

18.6 + 113.4 + x = 180

132 + x = 180

x = 180 - 132

x = 48

5 0
3 years ago
PLEASE HELP! Answer only if correct, please. :)
s2008m [1.1K]

Answer:

Solid dot on -7 with the line going to the right towards 0

Step-by-step explanation:

5 0
3 years ago
Due Soon Need Help Geometry!
AveGali [126]

 

Some basic formulas involving triangles

\ a^2 = b^2 + c^2 - 2bc \textrm{ cos } \alphaa  2 =b  2+2 + c 2

−2bc cos α

\ b^2 = a^2 + c^2 - 2ac \textrm{ cos } \betab   2=

 

m_b^2 = \frac{1}{4}( 2a^2 + 2c^2 - b^2 )m   b2 = 41(2a 2 + 2c 2-b 2)

b

Bisector formulas

\ \frac{a}{b} = \frac{m}{n}  ba =nm  

​  

 

\ l^2 = ab - mnl  2=ab-mm

A = \frac{1}{2}a\cdot b = \frac{1}{2}c\cdot hA=  

\ A = \sqrt{p(p - a)(p - b)(p - c)}A=  

p(p−a)(p−b)(p−c)

​  

 

\iits whatever  A = prA=pr with r we denote the radius of the triangle inscribed circle

\ A = \frac{abc}{4R}A=  

4R

abc

​  

 - R is the radius of the prescribed circle

\ A = \sqrt{p(p - a)(p - b)(p - c)}A=  

p(p−a)(p−b)(p−c)

​  

5 0
2 years ago
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